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A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?
  • a)
    12
  • b)
    16
  • c)
    18
  • d)
    24
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A student got twice as many sums wrong as he got right. If he attempte...
Suppose the boy got x sums right and 2x sums wrong.
Then, x + 2x = 48 3x = 48 x = 16.
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Most Upvoted Answer
A student got twice as many sums wrong as he got right. If he attempte...
To solve this problem, let's assume that the student got x sums right.

Given that the student got twice as many sums wrong as he got right, the number of sums he got wrong would be 2x.

The total number of sums attempted by the student is 48. Therefore, we can write the equation:

x + 2x = 48

Simplifying the equation, we get:

3x = 48

Dividing both sides by 3, we find:

x = 16

Therefore, the student solved 16 sums correctly.

Hence, the correct answer is option B) 16.
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A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?a)12b)16c)18d)24Correct answer is option 'B'. Can you explain this answer? for LR 2025 is part of LR preparation. The Question and answers have been prepared according to the LR exam syllabus. Information about A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?a)12b)16c)18d)24Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for LR 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A student got twice as many sums wrong as he got right. If he attempted 48 sums in all, how many did he solve correctly ?a)12b)16c)18d)24Correct answer is option 'B'. Can you explain this answer?.
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