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In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score ?
  • a)
    62
  • b)
    45
  • c)
    28
  • d)
    20
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In a cricket match, five batsmen A, B, C, D and E scored an average of...
Total runs scored = (36 x 5) = 180.
Let the runs scored by E be x.
Then, runs scored by D = x + 5; runs scored by A = x + 8;
runs scored by B = x + x + 5 = 2x + 5;
runs scored by C = (107 - B) = 107 - (2x + 5) = 102 - 2x.
So, total runs = (x + 8) + (2x + 5) + (102 - 2x) + (x + 5) + x = 3x + 120.
Therefore 3x + 120 =180 3X = 60 x = 20.
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Most Upvoted Answer
In a cricket match, five batsmen A, B, C, D and E scored an average of...
**Given Information:**

- Average score of five batsmen A, B, C, D, and E is 36 runs.
- D scored 5 more runs than E.
- E scored 8 fewer runs than A.
- B scored as many runs as D and E combined.
- B and C scored a total of 107 runs.

**Let's assume the runs scored by each player:**

- Let A score x runs.
- Then E will score x - 8 runs (as E scored 8 fewer runs than A).
- D will score (x - 8) + 5 runs (as D scored 5 more runs than E).
- B will score (x - 8) + 5 + (x - 8) runs (as B scored as many runs as D and E combined).
- C will score 107 - (runs scored by B) runs (as B and C scored a total of 107 runs).

**Calculating the average score:**

- The total runs scored by all five batsmen = x + (x - 8) + 5 + (x - 8) + (x - 8) + 5 + 107 - (runs scored by B)
- The total runs scored by all five batsmen = 5x - 14 + 5 + 107 - (runs scored by B)
- The total runs scored by all five batsmen = 5x + 98 - (runs scored by B)
- The average score of all five batsmen = (5x + 98 - (runs scored by B))/5

Since the average score of all five batsmen is given as 36 runs, we can set up the equation:

(5x + 98 - (runs scored by B))/5 = 36

**Simplifying the equation:**

- 5x + 98 - (runs scored by B) = 36 * 5
- 5x + 98 - (runs scored by B) = 180
- 5x - (runs scored by B) = 82

**Substituting the value of runs scored by B:**

- As per the given information, B scored (x - 8) + 5 + (x - 8) runs
- Substituting this value in the equation:
5x - [(x - 8) + 5 + (x - 8)] = 82
5x - (2x - 16) - 10 = 82
5x - 2x + 16 - 10 = 82
3x + 6 = 82
3x = 82 - 6
3x = 76
x = 76/3
x = 25.33

**Calculating the runs scored by E:**

- E scored x - 8 runs
- Substituting the value of x:
E scored 25.33 - 8 = 17.33 runs

Since the runs scored by a player cannot be in decimal points, we round off the value of E's score to the nearest whole number.

Hence, E scored approximately 17 runs.

The correct answer is option 'D' (20 runs), which indicates that there might be an error in the calculations or assumptions made.
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In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score ?a)62b)45c)28d)20Correct answer is option 'D'. Can you explain this answer?
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