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Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?
  • a)
    Rs. 4, Rs. 23
  • b)
    Rs. 13, Rs. 17
  • c)
    Rs. 15, Rs. 14
  • d)
    Rs. 17, Rs. 13
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Two bus tickets from city A to B and three tickets from city A to C co...
Let Rs. x be the fare of city B from city A and Rs. y be the fare of city C from city A.
Then, 2x + 3y = 77 ...(i) and
3x + 2y = 73 ...(ii)
Multiplying (i) by 3 and (ii) by 2 and subtracting, we get: 5y = 85 or y = 17.
Putting y = 17 in (i), we get: x = 13.
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Most Upvoted Answer
Two bus tickets from city A to B and three tickets from city A to C co...
Given:
2B + 3C = 77 ...(1)
3B + 2C = 73 ...(2)

To find: Fares for B and C from A

Solution:
Let the fare of city B from A be x and city C from A be y.

From equation (1), we have:
2x + 3y = 77

From equation (2), we have:
3x + 2y = 73

Now, we need to solve these two equations simultaneously to find the values of x and y.

Method 1: Elimination method
Multiplying equation (1) by 2 and equation (2) by 3, we get:
4x + 6y = 154
9x + 6y = 219

Subtracting equation (1) from equation (2), we get:
5x = 65
x = 13

Substituting the value of x in equation (1), we get:
2(13) + 3y = 77
26 + 3y = 77
3y = 51
y = 17

Therefore, the fares for cities B and C from A are Rs. 13 and Rs. 17, respectively.

Method 2: Substitution method
From equation (1), we have:
y = (77 - 2x)/3

Substituting this value of y in equation (2), we get:
3x + 2(77 - 2x)/3 = 73

Simplifying, we get:
9x + 154 - 4x = 219
5x = 65
x = 13

Substituting the value of x in equation (1), we get:
2(13) + 3y = 77
26 + 3y = 77
3y = 51
y = 17

Therefore, the fares for cities B and C from A are Rs. 13 and Rs. 17, respectively.

Answer: The correct option is (b) Rs. 13, Rs. 17.
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Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?a)Rs. 4, Rs. 23b)Rs. 13, Rs. 17c)Rs. 15, Rs. 14d)Rs. 17, Rs. 13Correct answer is option 'B'. Can you explain this answer?
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Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?a)Rs. 4, Rs. 23b)Rs. 13, Rs. 17c)Rs. 15, Rs. 14d)Rs. 17, Rs. 13Correct answer is option 'B'. Can you explain this answer? for LR 2025 is part of LR preparation. The Question and answers have been prepared according to the LR exam syllabus. Information about Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?a)Rs. 4, Rs. 23b)Rs. 13, Rs. 17c)Rs. 15, Rs. 14d)Rs. 17, Rs. 13Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for LR 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?a)Rs. 4, Rs. 23b)Rs. 13, Rs. 17c)Rs. 15, Rs. 14d)Rs. 17, Rs. 13Correct answer is option 'B'. Can you explain this answer?.
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