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A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?
- a)22
- b)23
- c)25
- d)35
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A, B, C, D and E play a game of cards. A says to B, "If you give me th...
Clearly, we have :
B-3 = E ...(i)
B + 3 = D ...(ii)
A+B = D + E+10 ...(iii)
B = C + 2 ...(iv)
A+B + C + D + E= 133 ...(v)
From (i) and (ii), we have : 2 B = D + E ...(vi)
From (iii) and (vi), we have : A = B + 10 ...(vii)
Using (iv), (vi) and (vii) in (v), we get:
(B + 10) + B + (B - 2) + 2B = 133 
5B = 125 
B = 25.
5B = 125 B = 25.Most Upvoted Answer
A, B, C, D and E play a game of cards. A says to B, "If you give me th...
Problem Analysis:
Let's break down the given information:
- A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has."
- A and B together have 10 cards more than what D and E together have.
- B has two cards more than what C has.
- The total number of cards is 133.
Solution:
Let's assume the number of cards with A, B, C, D, and E as a, b, c, d, and e respectively.
From the given information, we can form the following equations:
1) A + 3 = e and B + 3 = d
(If B gives A three cards, then B will have as many cards as E has, and if A gives B three cards, then B will have as many cards as D has.)
2) A + B = D + E + 10
(A and B together have 10 cards more than what D and E together have.)
3) B = C + 2
(B has two cards more than what C has.)
4) A + B + C + D + E = 133
(The total number of cards is 133.)
From equation 1, we can write the following:
A = e - 3 and B = d - 3
Substituting these values in equation 2, we get:
(e - 3) + (d - 3) = D + E + 10
e + d - 6 = D + E + 10
e + d - D - E = 16 ...(equation 5)
Substituting the value of B from equation 3 in equation 1, we get:
C + 2 = d - 3
d = C + 5
Substituting the values of A, B, and d in equation 4, we get:
(e - 3) + (d - 3) + C + (C + 5) + E = 133
2C + E + e + d - 6 = 133
2C + E + e + C + 5 - 6 = 133 ...(substituting the value of d)
3C + E + e - 1 = 133
3C + E + e = 134 ...(equation 6)
Adding equation 5 and equation 6, we get:
e + d - D - E + 3C + E + e = 16 + 134
2e + d - D + 3C = 150
But we know that e + d - D - E = 16 from equation 5, so substituting this value, we get:
2e + 16 + 3C = 150
2e + 3C = 134 ...(equation 7)
Now, let's find the possible values of e and C.
From equation 7, we can see that e and C must be even numbers since 3C is divisible by 3 and 134 is even.
The possible values of e and C are:
e = 2, C = 44
e = 4, C = 42
e =
Let's break down the given information:
- A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has."
- A and B together have 10 cards more than what D and E together have.
- B has two cards more than what C has.
- The total number of cards is 133.
Solution:
Let's assume the number of cards with A, B, C, D, and E as a, b, c, d, and e respectively.
From the given information, we can form the following equations:
1) A + 3 = e and B + 3 = d
(If B gives A three cards, then B will have as many cards as E has, and if A gives B three cards, then B will have as many cards as D has.)
2) A + B = D + E + 10
(A and B together have 10 cards more than what D and E together have.)
3) B = C + 2
(B has two cards more than what C has.)
4) A + B + C + D + E = 133
(The total number of cards is 133.)
From equation 1, we can write the following:
A = e - 3 and B = d - 3
Substituting these values in equation 2, we get:
(e - 3) + (d - 3) = D + E + 10
e + d - 6 = D + E + 10
e + d - D - E = 16 ...(equation 5)
Substituting the value of B from equation 3 in equation 1, we get:
C + 2 = d - 3
d = C + 5
Substituting the values of A, B, and d in equation 4, we get:
(e - 3) + (d - 3) + C + (C + 5) + E = 133
2C + E + e + d - 6 = 133
2C + E + e + C + 5 - 6 = 133 ...(substituting the value of d)
3C + E + e - 1 = 133
3C + E + e = 134 ...(equation 6)
Adding equation 5 and equation 6, we get:
e + d - D - E + 3C + E + e = 16 + 134
2e + d - D + 3C = 150
But we know that e + d - D - E = 16 from equation 5, so substituting this value, we get:
2e + 16 + 3C = 150
2e + 3C = 134 ...(equation 7)
Now, let's find the possible values of e and C.
From equation 7, we can see that e and C must be even numbers since 3C is divisible by 3 and 134 is even.
The possible values of e and C are:
e = 2, C = 44
e = 4, C = 42
e =
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A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?a)22b)23c)25d)35Correct answer is option 'C'. Can you explain this answer?
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A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?a)22b)23c)25d)35Correct answer is option 'C'. Can you explain this answer? for LR 2025 is part of LR preparation. The Question and answers have been prepared according to the LR exam syllabus. Information about A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?a)22b)23c)25d)35Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for LR 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A, B, C, D and E play a game of cards. A says to B, "If you give me three cards, you will have as many as E has and if I give you three cards, you will have as many as D has." A and B together have 10 cards more than what D and E together have. If B has two cards more than what C has and the total number of cards be 133, how many cards does B have ?a)22b)23c)25d)35Correct answer is option 'C'. Can you explain this answer?.
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