Point R is 10 metres north of point A. Point K is exactly in the middl...
To find the distance between points S and N, we need to determine the coordinates of these two points and then calculate the distance using the distance formula.
- Finding the coordinates of points R, A, K, N, M, and S:
Given that point R is 10 metres north of point A, we can say that the y-coordinate of R is 10 units greater than the y-coordinate of A. Let's assume the coordinates of point A are (x, y). Therefore, the coordinates of point R will be (x, y + 10).
Point K is exactly in the middle of points R and A. So, the x-coordinate of K will be the average of the x-coordinates of R and A, and the y-coordinate of K will be the average of the y-coordinates of R and A. Therefore, the coordinates of point K will be ((x + x) / 2, (y + y + 10) / 2), which simplifies to (x, y + 5).
Point N is 7 metres east of point A. Since N is to the east, the x-coordinate of N will be 7 units greater than the x-coordinate of A. Therefore, the coordinates of point N will be (x + 7, y).
Point M is 7 metres east of point K. Similar to N, the x-coordinate of M will be 7 units greater than the x-coordinate of K. Therefore, the coordinates of point M will be (x + 7, y + 5).
Point S is 6 metres north of point M. So, the y-coordinate of S will be 6 units greater than the y-coordinate of M. Therefore, the coordinates of point S will be (x + 7, y + 5 + 6), which simplifies to (x + 7, y + 11).
- Calculating the distance between points S and N:
To find the distance between two points, we can use the distance formula, which is given by:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the coordinates of S are (x + 7, y + 11) and the coordinates of N are (x + 7, y). Plugging these values into the distance formula, we get:
Distance = √(((x + 7) - (x + 7))^2 + ((y + 11) - y)^2)
= √(0^2 + 11^2)
= √(0 + 121)
= √121
= 11
Therefore, the distance between points S and N is 11 metres. Hence, the correct answer is option C.