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A self-fertilizing trihybrid plant forms
[2004]
- a)8 different gametes and 64 different zygotes
- b)4 different gametes and 16 different zygotes
- c)8 different gametes and 16 different zygotes
- d)8 different gametes and 32 different zygotes
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A self-fertilizing trihybrid plant forms[2004]a)8 different gametes an...
A self-fertilizing trihybrid plant forms 8 different gametes and 64 different zygotes. The genotype of trihybrid plant is AaBbCc. Number of gametes formed = 2n = 23 = 8 Here n = no. of heterozygosity = 3 in present case.
No. of zygotes formed = 82 = 64.
No. of zygotes formed = 82 = 64.
Most Upvoted Answer
A self-fertilizing trihybrid plant forms[2004]a)8 different gametes an...
Formation of gametes in self-fertilizing trihybrid plant
A self-fertilizing trihybrid plant would have three pairs of contrasting traits. For example, let's consider three pairs of traits - A/a, B/b, and C/c.
During gamete formation, the alleles segregate independently of each other, following the law of independent assortment. This means that the different alleles for each trait would separate randomly into gametes, resulting in eight different possible gametes.
The possible gametes that can be formed in this case are:
- ABC
- ABc
- AbC
- Abc
- aBC
- aBc
- abC
- abc
Formation of zygotes
When two gametes unite, they form a zygote with two alleles for each trait. The number of different possible zygotes can be calculated by multiplying the number of possible alleles for each trait.
In this case, each trait has two possible alleles (A or a, B or b, and C or c). Therefore, the number of possible zygotes can be calculated as:
2 x 2 x 2 = 8
This means that there are 8 different possible zygotes that can be formed when two gametes unite.
Total number of possible zygotes
To calculate the total number of possible zygotes, we need to multiply the number of different possible gametes by the number of different possible zygotes that can be formed from each gamete.
In this case, there are 8 different possible gametes and each gamete can form 8 different possible zygotes. Therefore, the total number of possible zygotes can be calculated as:
8 x 8 = 64
Therefore, a self-fertilizing trihybrid plant can form 8 different gametes and 64 different zygotes. The correct option is (a).
A self-fertilizing trihybrid plant would have three pairs of contrasting traits. For example, let's consider three pairs of traits - A/a, B/b, and C/c.
During gamete formation, the alleles segregate independently of each other, following the law of independent assortment. This means that the different alleles for each trait would separate randomly into gametes, resulting in eight different possible gametes.
The possible gametes that can be formed in this case are:
- ABC
- ABc
- AbC
- Abc
- aBC
- aBc
- abC
- abc
Formation of zygotes
When two gametes unite, they form a zygote with two alleles for each trait. The number of different possible zygotes can be calculated by multiplying the number of possible alleles for each trait.
In this case, each trait has two possible alleles (A or a, B or b, and C or c). Therefore, the number of possible zygotes can be calculated as:
2 x 2 x 2 = 8
This means that there are 8 different possible zygotes that can be formed when two gametes unite.
Total number of possible zygotes
To calculate the total number of possible zygotes, we need to multiply the number of different possible gametes by the number of different possible zygotes that can be formed from each gamete.
In this case, there are 8 different possible gametes and each gamete can form 8 different possible zygotes. Therefore, the total number of possible zygotes can be calculated as:
8 x 8 = 64
Therefore, a self-fertilizing trihybrid plant can form 8 different gametes and 64 different zygotes. The correct option is (a).
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Community Answer
A self-fertilizing trihybrid plant forms[2004]a)8 different gametes an...
No of gametes =2^n=2^3=8
no of zygote=8^2=64
thus 8 different gametes and 64 different zygote
no of zygote=8^2=64
thus 8 different gametes and 64 different zygote
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A self-fertilizing trihybrid plant forms[2004]a)8 different gametes and 64 different zygotesb)4 different gametes and 16 different zygotesc)8 different gametes and 16 different zygotesd)8 different gametes and 32 different zygotesCorrect answer is option 'A'. Can you explain this answer?
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