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Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and another amount at 10% SI per annum. The total interest earned at the end of one year will be same as interest earned when the total amount invested at 6% SI per annum. Find the total amount invested?
  • a)
    Rs.12000
  • b)
    Rs.24000
  • c)
    Rs.30000
  • d)
    Rs.36000
  • e)
    None
Correct answer is option 'D'. Can you explain this answer?
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Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and anot...
Answer – 4.Rs.36000 Explanation : 24000*4/100 = 960
x*10/100 = 0.1x 960+0.1x = (24000+x)*6/100 x =12000 Total = 24,000+12,000 = 36,000
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Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and anot...
Answer – 4.Rs.36000 Explanation : 24000*4/100 = 960
x*10/100 = 0.1x 960+0.1x = (24000+x)*6/100 x =12000 Total = 24,000+12,000 = 36,000
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Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and anot...
Problem Statement: Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and another amount at 10% SI per annum. The total interest earned at the end of one year will be same as interest earned when the total amount invested at 6% SI per annum. Find the total amount invested.

Solution:

Let us assume that Nitin invested x amount at 4% SI per annum and (24000 - x) amount at 10% SI per annum.

Interest earned on x at 4% SI per annum in one year = (x * 4 * 1) / 100 = 0.04x

Interest earned on (24000 - x) at 10% SI per annum in one year = [(24000 - x) * 10 * 1] / 100 = 2400 - 0.1x

Total interest earned in one year = 0.04x + 2400 - 0.1x = 2400 - 0.06x

Now, as per the question, the interest earned when the total amount is invested at 6% SI per annum is the same as the total interest earned in the above case.

Let us assume that Nitin invested y amount at 6% SI per annum.

Interest earned on y at 6% SI per annum in one year = (y * 6 * 1) / 100 = 0.06y

Total interest earned in one year = 0.06y

As per the question, 0.06y = 2400 - 0.06x

Simplifying the above equation, we get:

0.06y + 0.06x = 2400

0.06(x+y) = 2400

x + y = 40000

Therefore, the total amount invested by Nitin is x + (24000-x) + y = 40000.

Simplifying the above equation, we get:

40000 + y = 40000

y = 0

Therefore, Nitin invested Rs. 24000 at 4% SI per annum and 0 amount at 10% SI per annum.

Hence, the correct answer is Option D.
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Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and another amount at 10% SI per annum. The total interest earned at the end of one year will be same as interest earned when the total amount invested at 6% SI per annum. Find the total amount invested?a)Rs.12000b)Rs.24000c)Rs.30000d)Rs.36000e)NoneCorrect answer is option 'D'. Can you explain this answer?
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Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and another amount at 10% SI per annum. The total interest earned at the end of one year will be same as interest earned when the total amount invested at 6% SI per annum. Find the total amount invested?a)Rs.12000b)Rs.24000c)Rs.30000d)Rs.36000e)NoneCorrect answer is option 'D'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and another amount at 10% SI per annum. The total interest earned at the end of one year will be same as interest earned when the total amount invested at 6% SI per annum. Find the total amount invested?a)Rs.12000b)Rs.24000c)Rs.30000d)Rs.36000e)NoneCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Nitin invested an amount of Rs. 24000 at the 4% SI per annum, and another amount at 10% SI per annum. The total interest earned at the end of one year will be same as interest earned when the total amount invested at 6% SI per annum. Find the total amount invested?a)Rs.12000b)Rs.24000c)Rs.30000d)Rs.36000e)NoneCorrect answer is option 'D'. Can you explain this answer?.
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