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A number when successively divided by 4, 7, 9 leaves remainder 2, 0, 6 respectively. Find the remainder when the smallest such number is divided by 37.
  • a)
    15
  • b)
    14
  • c)
    11
  • d)
    24
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A number when successively divided by 4, 7, 9 leaves remainder 2, 0, 6...
⇒ Number is in the form = 4{7(9k + 6) + 0} + 2 = 4(63k + 42 + 0) + 2 = 252k + 170
For the smallest number k = 1
⇒ Number = N = 422
Now,
⇒ 422 ÷ 37 = 11 × 37 + 15
∴ When the number is divided by 37 then the remainder is 15.
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A number when successively divided by 4, 7, 9 leaves remainder 2, 0, 6 respectively. Find the remainder when the smallest such number is divided by 37.a)15b)14c)11d)24Correct answer is option 'A'. Can you explain this answer?
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