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Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours respectively. In how much time the cistern will be full if A is operated for the whole time and B and C are operated alternately which B being first?
- a)10 hours 32 minutes
- b)6 hours
- c)
hours - d)
hours - e)
hours
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours re...
In first hour, part of cistern filled is (1/10 + 1/12) = 11/60
In second hour, part of cistern filled is (1/10 + 1/15) = 1/6
So in 2 hours, part of cistern filled is 11/60 + 10/60 = 21/60 = 7/20
now in 2*2 (4) hours, part of cistern filled is (7/20)*2 = 14/20 = 7/10
now in the 5th hour, A+B’s turn which fill 11/60 in that hour, but the cistern remaining to be filled is (1 – 7/10) = 3/10, since 3/10 is more than 11/60, so after 5th hour remaining part to be filled is 3/10 – 11/60 = 7/60
now in 6th hour, (A+C)’s turn, it will fill remaining 7/60 in (7/60)*(6/1) = 7/10 so total 5 7/10 hours
In second hour, part of cistern filled is (1/10 + 1/15) = 1/6
So in 2 hours, part of cistern filled is 11/60 + 10/60 = 21/60 = 7/20
now in 2*2 (4) hours, part of cistern filled is (7/20)*2 = 14/20 = 7/10
now in the 5th hour, A+B’s turn which fill 11/60 in that hour, but the cistern remaining to be filled is (1 – 7/10) = 3/10, since 3/10 is more than 11/60, so after 5th hour remaining part to be filled is 3/10 – 11/60 = 7/60
now in 6th hour, (A+C)’s turn, it will fill remaining 7/60 in (7/60)*(6/1) = 7/10 so total 5 7/10 hours
Most Upvoted Answer
Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours re...
In first hour, part of cistern filled is (1/10 + 1/12) = 11/60
In second hour, part of cistern filled is (1/10 + 1/15) = 1/6
So in 2 hours, part of cistern filled is 11/60 + 10/60 = 21/60 = 7/20
now in 2*2 (4) hours, part of cistern filled is (7/20)*2 = 14/20 = 7/10
now in the 5th hour, A+B’s turn which fill 11/60 in that hour, but the cistern remaining to be filled is (1 – 7/10) = 3/10, since 3/10 is more than 11/60, so after 5th hour remaining part to be filled is 3/10 – 11/60 = 7/60
now in 6th hour, (A+C)’s turn, it will fill remaining 7/60 in (7/60)*(6/1) = 7/10 so total 5 7/10 hours
In second hour, part of cistern filled is (1/10 + 1/15) = 1/6
So in 2 hours, part of cistern filled is 11/60 + 10/60 = 21/60 = 7/20
now in 2*2 (4) hours, part of cistern filled is (7/20)*2 = 14/20 = 7/10
now in the 5th hour, A+B’s turn which fill 11/60 in that hour, but the cistern remaining to be filled is (1 – 7/10) = 3/10, since 3/10 is more than 11/60, so after 5th hour remaining part to be filled is 3/10 – 11/60 = 7/60
now in 6th hour, (A+C)’s turn, it will fill remaining 7/60 in (7/60)*(6/1) = 7/10 so total 5 7/10 hours
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Community Answer
Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours re...
In first hour, part of cistern filled is (1/10 + 1/12) = 11/60
In second hour, part of cistern filled is (1/10 + 1/15) = 1/6
So in 2 hours, part of cistern filled is 11/60 + 10/60 = 21/60 = 7/20
now in 2*2 (4) hours, part of cistern filled is (7/20)*2 = 14/20 = 7/10
now in the 5th hour, A+B’s turn which fill 11/60 in that hour, but the cistern remaining to be filled is (1 – 7/10) = 3/10, since 3/10 is more than 11/60, so after 5th hour remaining part to be filled is 3/10 – 11/60 = 7/60
now in 6th hour, (A+C)’s turn, it will fill remaining 7/60 in (7/60)*(6/1) = 7/10 so total 5 7/10 hours
In second hour, part of cistern filled is (1/10 + 1/15) = 1/6
So in 2 hours, part of cistern filled is 11/60 + 10/60 = 21/60 = 7/20
now in 2*2 (4) hours, part of cistern filled is (7/20)*2 = 14/20 = 7/10
now in the 5th hour, A+B’s turn which fill 11/60 in that hour, but the cistern remaining to be filled is (1 – 7/10) = 3/10, since 3/10 is more than 11/60, so after 5th hour remaining part to be filled is 3/10 – 11/60 = 7/60
now in 6th hour, (A+C)’s turn, it will fill remaining 7/60 in (7/60)*(6/1) = 7/10 so total 5 7/10 hours
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Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours respectively. In how much time the cistern will be full if A is operated for the whole time and B and C are operated alternately which B being first?a)10 hours 32 minutesb)6 hoursc)hoursd)hourse)hoursCorrect answer is option 'D'. Can you explain this answer?
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Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours respectively. In how much time the cistern will be full if A is operated for the whole time and B and C are operated alternately which B being first?a)10 hours 32 minutesb)6 hoursc)hoursd)hourse)hoursCorrect answer is option 'D'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours respectively. In how much time the cistern will be full if A is operated for the whole time and B and C are operated alternately which B being first?a)10 hours 32 minutesb)6 hoursc)hoursd)hourse)hoursCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours respectively. In how much time the cistern will be full if A is operated for the whole time and B and C are operated alternately which B being first?a)10 hours 32 minutesb)6 hoursc)hoursd)hourse)hoursCorrect answer is option 'D'. Can you explain this answer?.
Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours respectively. In how much time the cistern will be full if A is operated for the whole time and B and C are operated alternately which B being first?a)10 hours 32 minutesb)6 hoursc)hoursd)hourse)hoursCorrect answer is option 'D'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours respectively. In how much time the cistern will be full if A is operated for the whole time and B and C are operated alternately which B being first?a)10 hours 32 minutesb)6 hoursc)hoursd)hourse)hoursCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three pipes A, B and C can fill the cistern in 10, 12, and 15 hours respectively. In how much time the cistern will be full if A is operated for the whole time and B and C are operated alternately which B being first?a)10 hours 32 minutesb)6 hoursc)hoursd)hourse)hoursCorrect answer is option 'D'. Can you explain this answer?.
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