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If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 42 minutes, then the slower pipe alone will be able to fill the tank in?
- a)148 minutes
- b)124 minutes
- c)154 minutes
- d)168 minutes
- e)None of the Above
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
If a pipe A can fill a tank 3 times faster than pipe B. If both the pi...
Time is taken by pipe A = x
Time is taken by pipe B = x/3
1/x + 3/x = 1/42
x = 168 minutes
Time is taken by pipe B = x/3
1/x + 3/x = 1/42
x = 168 minutes
Most Upvoted Answer
If a pipe A can fill a tank 3 times faster than pipe B. If both the pi...
Time is taken by pipe A = x
Time is taken by pipe B = x/3
1/x + 3/x = 1/42
x = 168 minutes
Time is taken by pipe B = x/3
1/x + 3/x = 1/42
x = 168 minutes
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Community Answer
If a pipe A can fill a tank 3 times faster than pipe B. If both the pi...
Given:
- Pipe A can fill the tank 3 times faster than pipe B.
- Both pipes can fill the tank in 42 minutes.
To find:
The time taken by the slower pipe alone to fill the tank.
Assuming the slower pipe takes x minutes to fill the tank, we can determine the time taken by the faster pipe A as (x/3) minutes.
Total work done by both pipes together = Work done by pipe A + Work done by pipe B.
Let's calculate the work done by each pipe in terms of filling the tank completely:
- Work done by pipe A = (1 tank) / (x/3 minutes) = 3/x tanks per minute.
- Work done by pipe B = (1 tank) / x minutes = 1/x tanks per minute.
Since both pipes can fill the tank in 42 minutes, the combined work done by both pipes is equal to 1 tank in 42 minutes:
(3/x + 1/x) tanks per minute = 1 tank in 42 minutes.
Simplifying the equation:
4/x tanks per minute = 1 tank in 42 minutes.
Cross-multiplying:
4 * 42 = x.
168 = x.
Therefore, the slower pipe alone will be able to fill the tank in 168 minutes, which is option D.
- Pipe A can fill the tank 3 times faster than pipe B.
- Both pipes can fill the tank in 42 minutes.
To find:
The time taken by the slower pipe alone to fill the tank.
Assuming the slower pipe takes x minutes to fill the tank, we can determine the time taken by the faster pipe A as (x/3) minutes.
Total work done by both pipes together = Work done by pipe A + Work done by pipe B.
Let's calculate the work done by each pipe in terms of filling the tank completely:
- Work done by pipe A = (1 tank) / (x/3 minutes) = 3/x tanks per minute.
- Work done by pipe B = (1 tank) / x minutes = 1/x tanks per minute.
Since both pipes can fill the tank in 42 minutes, the combined work done by both pipes is equal to 1 tank in 42 minutes:
(3/x + 1/x) tanks per minute = 1 tank in 42 minutes.
Simplifying the equation:
4/x tanks per minute = 1 tank in 42 minutes.
Cross-multiplying:
4 * 42 = x.
168 = x.
Therefore, the slower pipe alone will be able to fill the tank in 168 minutes, which is option D.
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If a pipe A can fill a tank 3 times faster than pipe B. If both the pipes can fill the tank in 42 minutes, then the slower pipe alone will be able to fill the tank in?a)148 minutesb)124 minutesc)154 minutesd)168 minutese)None of the AboveCorrect answer is option 'D'. Can you explain this answer?
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