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There are two numbers such that the first number is half of the second number. If their average is 57, then what is the first number?
  • a)
    19
  • b)
    38
  • c)
    21
  • d)
    29
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
There are two numbers such that the first number is half of the second...
GIVEN:
Average of two numbers = 57
FORMULA USED:
Average of two numbers (a, b) = (a + b)/2
CALCULATION:
Let the first number be ‘x’
⇒ Second number = 2x
Now, average = 57
⇒ (x + 2x)/2 = 57
⇒ 3x = 114
⇒ x = 114/3 = 38
∴ The first number is 38
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Most Upvoted Answer
There are two numbers such that the first number is half of the second...
Given:
- There are two numbers, let's call them x and y.
- The first number is half of the second number, which can be written as x = y/2.
- The average of the two numbers is 57.

To find the first number, we need to solve the given information.

1. Find the relationship between the two numbers
- We are given that the first number is half of the second number, so we can write x = y/2.

2. Find the average of the two numbers
- The average of two numbers is the sum of the numbers divided by 2.
- Since we are given that the average is 57, we can write (x + y)/2 = 57.

3. Substitute the value of x from the first equation into the second equation
- Replace x with y/2 in the second equation: (y/2 + y)/2 = 57.

4. Simplify the equation
- Multiply both sides of the equation by 2 to eliminate the fraction: y + 2y = 4 * 57.
- Combine like terms: 3y = 228.

5. Solve for y
- Divide both sides of the equation by 3: y = 76.

6. Find the value of x
- Substitute the value of y back into the first equation: x = 76/2.
- Simplify: x = 38.

Therefore, the first number is 38.
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There are two numbers such that the first number is half of the second number. If their average is 57, then what is the first number?a)19b)38c)21d)29Correct answer is option 'B'. Can you explain this answer?
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