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A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another body of same mass moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is? A) v (B) 2v (C) 4v (D) 8v?
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A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another...
Solution:

Conservation of momentum states that the total momentum of an isolated system remains constant if no external force acts on it.

Initial momentum of the system = m × v + (-m) × v = 0

Final momentum of the system = 2mv (both bodies moving in the same direction)

By applying conservation of momentum, we can write:

Initial momentum = Final momentum

0 = 2mv + Vf (where Vf is the common final velocity of both bodies)

Vf = -2v (opposite direction to the initial direction of both bodies)

Hence, the common velocity of both the bodies after collision is 2v in the opposite direction to their initial direction.

Answer: (B) 2v
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A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another...
2v
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A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another body of same mass moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is? A) v (B) 2v (C) 4v (D) 8v?
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