Quant Exam > Quant Questions > Find the chance of throwing at least one ace ...
Start Learning for Free
Find the chance of throwing at least one ace in a simple throw with two dice
- a)1/12
- b)1/3
- c)1/4
- d)11/36
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Find the chance of throwing at least one ace in a simple throw with tw...
The possible number of cases is 6×6, or 36.
An ace on one die may be associated with any of the 6 numbers on the other die, and the remaining 5 numbers on the first die may each be associated with the ace on the second die; thus the number of favourable cases is 11.
Therefore the required chance is 11/36
An ace on one die may be associated with any of the 6 numbers on the other die, and the remaining 5 numbers on the first die may each be associated with the ace on the second die; thus the number of favourable cases is 11.
Therefore the required chance is 11/36
Free Test
FREE
| Start Free Test |
Community Answer
Find the chance of throwing at least one ace in a simple throw with tw...
Problem: Find the chance of throwing at least one ace in a simple throw with two dice.
Solution:
To find the chance of throwing at least one ace, we need to calculate the probability of not throwing any aces and subtract it from 1.
Step 1: Calculate the probability of not throwing any aces:
There are 6 possible outcomes for each dice, as it has 6 faces numbered from 1 to 6. Therefore, the total number of possible outcomes for two dice is 6 * 6 = 36.
In order not to throw any aces, both dice must show numbers other than 1. There are 5 possible outcomes for each dice that are not an ace (2, 3, 4, 5, and 6), so the probability of not throwing an ace on one dice is 5/6.
Since the throws of the two dice are independent events, we can multiply the probabilities together to find the probability of not throwing any aces on both dice:
P(not throwing any aces) = (5/6) * (5/6) = 25/36
Step 2: Calculate the probability of throwing at least one ace:
The probability of throwing at least one ace is equal to 1 - P(not throwing any aces). Therefore:
P(throwing at least one ace) = 1 - P(not throwing any aces) = 1 - 25/36 = 11/36
Conclusion:
The chance of throwing at least one ace in a simple throw with two dice is 11/36, which corresponds to option 'D' in the given choices.
Solution:
To find the chance of throwing at least one ace, we need to calculate the probability of not throwing any aces and subtract it from 1.
Step 1: Calculate the probability of not throwing any aces:
There are 6 possible outcomes for each dice, as it has 6 faces numbered from 1 to 6. Therefore, the total number of possible outcomes for two dice is 6 * 6 = 36.
In order not to throw any aces, both dice must show numbers other than 1. There are 5 possible outcomes for each dice that are not an ace (2, 3, 4, 5, and 6), so the probability of not throwing an ace on one dice is 5/6.
Since the throws of the two dice are independent events, we can multiply the probabilities together to find the probability of not throwing any aces on both dice:
P(not throwing any aces) = (5/6) * (5/6) = 25/36
Step 2: Calculate the probability of throwing at least one ace:
The probability of throwing at least one ace is equal to 1 - P(not throwing any aces). Therefore:
P(throwing at least one ace) = 1 - P(not throwing any aces) = 1 - 25/36 = 11/36
Conclusion:
The chance of throwing at least one ace in a simple throw with two dice is 11/36, which corresponds to option 'D' in the given choices.
|
Explore Courses for Quant exam
|
|
Top Courses for QuantView all
Question Description
Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer?.
Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer? for Quant 2025 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Quant 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer?.
Solutions for Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Quant.
Download more important topics, notes, lectures and mock test series for Quant Exam by signing up for free.
Here you can find the meaning of Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer?, a detailed solution for Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Find the chance of throwing at least one ace in a simple throw with two dicea)1/12b)1/3c)1/4d)11/36Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Quant tests.
|
|
Explore Courses for Quant exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup