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A train travelling at 38 kmph crosses a bus having 1/4th its length and travelling in the same direction at 20 kmph, in 60 seconds. It also crosses a railway platform in 72 seconds then the length of the platform is –
- a)520 m
- b)600 m
- c)720 m
- d)760 m
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
A train travelling at 38 kmph crosses a bus having 1/4thits length and...
Let the length of the train be A meters.
Length of the bus = A/4 meters
Relative speed = 38 – 20 = 18 kmph
⇒ 18 × 5/18 = 5 m/sec
Length of the bus = A/4 meters
Relative speed = 38 – 20 = 18 kmph
⇒ 18 × 5/18 = 5 m/sec
Given,
⇒ (A + A/4)/5 = 60
⇒ A = 240 m
Let the length of the platform be B meter.
Speed of the train = 38 × 5/18 = 95/9 m/sec
⇒ (A + A/4)/5 = 60
⇒ A = 240 m
Let the length of the platform be B meter.
Speed of the train = 38 × 5/18 = 95/9 m/sec
Then,
⇒ (240 + B) × 9/95 = 72
⇒ 240 + B = 760
⇒ B = 760 – 240
⇒ B = 520 m
∴ Length of platform is 520 m.
⇒ (240 + B) × 9/95 = 72
⇒ 240 + B = 760
⇒ B = 760 – 240
⇒ B = 520 m
∴ Length of platform is 520 m.
Most Upvoted Answer
A train travelling at 38 kmph crosses a bus having 1/4thits length and...
Given Data:
Speed of train (T) = 38 kmph
Speed of bus (B) = 20 kmph
Time taken to cross bus = 60 seconds
Time taken to cross platform = 72 seconds
Calculating length of the bus:
Let the length of the bus be L km
Relative speed of train and bus = 38 - 20 = 18 kmph = 5 m/s
Time taken to cross the bus = Length of bus / Relative speed = L / 5
Given, time taken to cross the bus = 60 seconds
Therefore, L / 5 = 60
L = 60 * 5 = 300 m
Calculating length of the platform:
Let the length of the platform be P km
Time taken to cross the platform = Length of train + Length of platform / Speed of train
Given, time taken to cross the platform = 72 seconds
Speed of train = 38 kmph = 10.56 m/s
Length of train = 300 m
Therefore, 300 + P / 10.56 = 72
300 + P = 756.72
P = 756.72 - 300 = 456.72 m
Answer:
Therefore, the length of the platform is 520 m.
Speed of train (T) = 38 kmph
Speed of bus (B) = 20 kmph
Time taken to cross bus = 60 seconds
Time taken to cross platform = 72 seconds
Calculating length of the bus:
Let the length of the bus be L km
Relative speed of train and bus = 38 - 20 = 18 kmph = 5 m/s
Time taken to cross the bus = Length of bus / Relative speed = L / 5
Given, time taken to cross the bus = 60 seconds
Therefore, L / 5 = 60
L = 60 * 5 = 300 m
Calculating length of the platform:
Let the length of the platform be P km
Time taken to cross the platform = Length of train + Length of platform / Speed of train
Given, time taken to cross the platform = 72 seconds
Speed of train = 38 kmph = 10.56 m/s
Length of train = 300 m
Therefore, 300 + P / 10.56 = 72
300 + P = 756.72
P = 756.72 - 300 = 456.72 m
Answer:
Therefore, the length of the platform is 520 m.
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A train travelling at 38 kmph crosses a bus having 1/4thits length and travelling in the same direction at 20 kmph, in 60 seconds. It also crosses a railway platform in 72 seconds then the length of the platform is –a)520 mb)600 mc)720 md)760 mCorrect answer is option 'A'. Can you explain this answer?
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A train travelling at 38 kmph crosses a bus having 1/4thits length and travelling in the same direction at 20 kmph, in 60 seconds. It also crosses a railway platform in 72 seconds then the length of the platform is –a)520 mb)600 mc)720 md)760 mCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A train travelling at 38 kmph crosses a bus having 1/4thits length and travelling in the same direction at 20 kmph, in 60 seconds. It also crosses a railway platform in 72 seconds then the length of the platform is –a)520 mb)600 mc)720 md)760 mCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A train travelling at 38 kmph crosses a bus having 1/4thits length and travelling in the same direction at 20 kmph, in 60 seconds. It also crosses a railway platform in 72 seconds then the length of the platform is –a)520 mb)600 mc)720 md)760 mCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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