Based on the equation e=-2×10^18 (1/n^2-1/n^2) the wavelength of the l...
Energy requires to Exide from n=1 to n=2 Ground state energy level is (E1)= -13.6 ev and second energy level is (E2)degree -3.4 ev There for E2-E1= -3.4-13.6= 10.2 ev 1 ev= 1.602 *10-19 = 10.2*(1.602*10-19) = 16.34*10-19 There for E= hc/`\ Wavelength= hc/E = (6.62*10-34)*(3*108)/16.34*10-19 = 1.215*10-7
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Based on the equation e=-2×10^18 (1/n^2-1/n^2) the wavelength of the l...
Calculating the Wavelength for Hydrogen Electron Excitation
To calculate the wavelength of light required to excite a hydrogen electron from level n=1 to level n=2, we can use the equation e=-2×10^18 (1/n^2-1/n^2).
Given Equation:
e = -2×10^18 (1/n^2 - 1/n^2)
Identifying the Initial and Final States:
- Initial state (n₁) = 1
- Final state (n₂) = 2
Substitute the Values:
- Substitute n₁ and n₂ into the equation:
e = -2×10^18 (1/1² - 1/2²)
e = -2×10^18 (1 - 1/4)
e = -2×10^18 (3/4)
e = -1.5×10^18
Calculating the Energy Change:
- The energy change (ΔE) is given by ΔE = -1.5×10^18 J
Using the Relationship between Energy and Wavelength:
- The relationship between energy and wavelength is E = hc/λ, where h is Planck's constant and c is the speed of light.
- Rearranging the equation for wavelength, we get λ = hc/ΔE
Calculating the Wavelength:
- Substitute the values of h, c, and ΔE into the equation:
λ = (6.626×10^-34 J s × 3.00×10^8 m/s) / (1.5×10^18 J)
λ = 1.325×10^-7 m
λ = 132.5 nm
Therefore, the wavelength of light that must be absorbed to excite a hydrogen electron from level n=1 to level n=2 is 132.5 nm.
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