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Two motor cars A and B start simultaneously from same point on two straight roads inclined at 60 degree to one another with velocities 30 km/h and 40 km/h respectively. The velocity of A with respect to B will be equal to?
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Two motor cars A and B start simultaneously from same point on two str...
Explanation:
Let's consider two roads AB and AC inclined at 60 degree to one another. Here, A is the common point where the two roads meet. Two cars A and B start simultaneously from point A at the same time.

Velocity of car A:
The velocity of car A is given as 30 km/h.

Velocity of car B:
The velocity of car B is given as 40 km/h.

Relative Velocity:
Relative velocity is defined as the velocity of one object with respect to another object.

Now, we need to find the velocity of car A with respect to car B.

We can use the vector method to find the relative velocity.

We can assume that the initial position of both cars is the origin.

Let's consider the velocity of car A as vector a and the velocity of car B as vector b.

We can represent the velocity of car A as a vector along AB and the velocity of car B as a vector along AC.

The velocity of car A with respect to car B can be represented as the vector difference a - b.

Vector Addition:
In order to find the vector difference, we need to add the negative of the vector b to the vector a.

Therefore, the velocity of car A with respect to car B can be represented as a - b.

Magnitude of Vector:
The magnitude of the vector difference is given by the formula:

|a - b| = sqrt((30^2 + 40^2) - 2*30*40*cos(60))

|a - b| = sqrt(900 + 1600 - 2400*0.5)

|a - b| = sqrt(900)

|a - b| = 30 km/h

Therefore, the velocity of car A with respect to car B is 30 km/h.
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Two motor cars A and B start simultaneously from same point on two str...
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Two motor cars A and B start simultaneously from same point on two straight roads inclined at 60 degree to one another with velocities 30 km/h and 40 km/h respectively. The velocity of A with respect to B will be equal to?
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