Neeraj is facing north, then he turns 45 degree right and goes 25 m, then turns in south – east direction to move 25 m and from there 25 m to east. In which direction/place is he from his original place?a)Northb)Eastc)Westd)SouthCorrect answer is option 'B'. Can you explain this answer?

Question

Neeraj is facing north, then he turns 45 degree right and goes 25 m, then turns in south &ndash; east direction to move 25 m and from there 25 m to east. In which direction/place is he from his original place?a)Northb)Eastc)Westd)SouthCorrect answer is option 'B'. Can you explain this answer?

Answer

Direction and goes 15 m. After that, he turns 90 degrees left and goes 30 m. Finally, he turns 180 degrees right and goes 20 m. What is Neeraj's final direction and how far is he from his starting point?

Neeraj's final direction can be determined by adding up all the turns he made.
He turned 45 degrees right initially, then 90 degrees left, and finally 180 degrees right.
45 degrees right + 90 degrees left + 180 degrees right = 225 degrees right.

Since 360 degrees make a full circle, 225 degrees right is equivalent to 360 degrees - 225 degrees = 135 degrees left.

Therefore, Neeraj's final direction is 135 degrees left.

To find the distance from his starting point, we need to calculate his net displacement in the north-south direction and the east-west direction.

He initially faced north, then turned south, so his net displacement in the north-south direction is 0 - 15 = -15 m (negative because it's in the south direction).

He turned 45 degrees right initially, then 180 degrees right, so his net displacement in the east-west direction is 25*cos(45) + 20*cos(180) = 17.68 + (-20) = -2.32 m (negative because it's in the west direction).

Using the Pythagorean theorem, the distance from his starting point is sqrt((-15)^2 + (-2.32)^2) = sqrt(225 + 5.38) = sqrt(230.38) ≈ 15.17 m.

Therefore, Neeraj's final direction is 135 degrees left, and he is approximately 15.17 m from his starting point.

Similar SSC Doubts

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