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Two flat glass plates are pressed together at the top edge and separated at the bottom edge by a strip of thin foil. The air wedge is examined in yellow sodium light (589 nm) reflected normally from its two surfaces, and 42 dark interference fringes are observed. Compute the thickness of the thin foil.
  • a)
    24.14 μm
  • b)
    12.07 mm
  • c)
    12.37 μm
  • d)
    12.07 μm
Correct answer is option 'D'. Can you explain this answer?
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Two flat glass plates are pressed together at the top edge and separat...
The correct answer is: 12.07 μm
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Two flat glass plates are pressed together at the top edge and separat...
To calculate the thickness of the thin foil, we can use the formula:

t = λ/(2m)

Where:
t = thickness of the thin foil
λ = wavelength of light (589 nm = 589 x 10^-9 m)
m = order of the interference fringe (42 fringes)

Plugging in the values:

t = (589 x 10^-9 m) / (2 x 42)
t = 589 x 10^-9 m / 84
t ≈ 7.01 x 10^-9 m

Converting to scientific notation:

t ≈ 7.01 nm

So, the thickness of the thin foil is approximately 7.01 nm.
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Two flat glass plates are pressed together at the top edge and separated at the bottom edge by a strip of thin foil. The air wedge is examined in yellow sodium light (589 nm) reflected normally from its two surfaces, and 42 dark interference fringes are observed. Compute the thickness of the thin foil.a)24.14μmb)12.07 mmc)12.37μmd)12.07μmCorrect answer is option 'D'. Can you explain this answer?
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