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Blue light of wavelength 480 nm is most strongly reflected from a thin film of oil on a glass slide when viewed near normal incidence. Assuming that the index of refraction of the oil is 1.2 & that of glass is 1.6, what is the minimum thickness of the oil film in nm (other than zero)?
    Correct answer is '200'. Can you explain this answer?
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    Blue light of wavelength 480 nm is most strongly reflected from a thin...
    Assuming the boundaries are vacuum-oil, oil-glass, then there will be a phase shift at the vacuum oil boundary since the refractive index of vacuum nvac < noil .. & another phase shift at the oil glass boundary because noil nglass That tells us that constructive interference happens for integer wavelength mλ.
    Light crosses a distance d in  but since its speed is lower in oil,

    Then

    ∴ The condition for constructive interference becomes 2 noild = mλ
    The next minimum thickness other than zero is when m = -1
    So, 
    The correct answer is: 200
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    Blue light of wavelength 480 nm is most strongly reflected from a thin...
    To determine the conditions for maximum reflection, we can use the equation for the optical path difference in a thin film:

    2nt = mλ,

    where n is the index of refraction of the medium the light is incident from (in this case, air), t is the thickness of the film, m is an integer representing the order of the reflection (m = 0 for the first order), and λ is the wavelength of light.

    In this case, since the light is incident from air, the index of refraction is 1.

    For maximum reflection of blue light with a wavelength of 480 nm, we can set up the equation as:

    2(1)(t) = m(480 nm).

    Since the question states that the blue light is most strongly reflected, we can assume that this corresponds to the first order reflection (m = 1).

    Therefore, we have:

    2t = 480 nm.

    Simplifying, we find:

    t = 240 nm.

    So, the thickness of the thin film of oil on the glass slide that results in maximum reflection of blue light is 240 nm.
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    Blue light of wavelength 480 nm is most strongly reflected from a thin film of oil on a glass slide when viewed near normal incidence. Assuming that the index of refraction of the oil is 1.2 & that of glass is 1.6, what is the minimum thickness of the oil film in nm (other than zero)?Correct answer is '200'. Can you explain this answer?
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    Blue light of wavelength 480 nm is most strongly reflected from a thin film of oil on a glass slide when viewed near normal incidence. Assuming that the index of refraction of the oil is 1.2 & that of glass is 1.6, what is the minimum thickness of the oil film in nm (other than zero)?Correct answer is '200'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about Blue light of wavelength 480 nm is most strongly reflected from a thin film of oil on a glass slide when viewed near normal incidence. Assuming that the index of refraction of the oil is 1.2 & that of glass is 1.6, what is the minimum thickness of the oil film in nm (other than zero)?Correct answer is '200'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Blue light of wavelength 480 nm is most strongly reflected from a thin film of oil on a glass slide when viewed near normal incidence. Assuming that the index of refraction of the oil is 1.2 & that of glass is 1.6, what is the minimum thickness of the oil film in nm (other than zero)?Correct answer is '200'. Can you explain this answer?.
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