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0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. The volume of water required for this dilution is.?
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0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. T...
Dilution of 0.5M, 20ml H3PO4 solution to obtain 0.1N H3PO4 solution
Given:
- Initial concentration of the H3PO4 solution (C1) = 0.5M
- Initial volume of the H3PO4 solution (V1) = 20ml
- Final concentration of the diluted H3PO4 solution (C2) = 0.1N
Formula:
The formula to calculate the volume of water required for dilution is:
V2 = (C1 * V1) / C2
Calculations:
Substituting the given values in the formula:
V2 = (0.5M * 20ml) / 0.1N
Conversion of units:
Since the concentration is given in moles per liter (M) and the volume is given in milliliters (ml), we need to convert the volume to liters.
V2 = (0.5M * 0.02L) / 0.1N
V2 = 0.01L / 0.1N
V2 = 0.1L
Result:
The volume of water required for dilution is 0.1 liters.
Explanation:
- The given H3PO4 solution has an initial concentration of 0.5M and a volume of 20ml.
- We need to dilute this solution to obtain a final concentration of 0.1N.
- To calculate the volume of water required for dilution, we use the formula V2 = (C1 * V1) / C2, where V2 is the volume of water required, C1 is the initial concentration, V1 is the initial volume, and C2 is the final concentration.
- Substituting the given values, we get V2 = (0.5M * 20ml) / 0.1N.
- Since the concentration is in moles per liter (M) and the volume is in milliliters (ml), we need to convert the volume to liters by dividing it by 1000 (1L = 1000ml).
- After converting the volume to liters, we get V2 = (0.5M * 0.02L) / 0.1N.
- Simplifying the equation, we get V2 = 0.01L / 0.1N = 0.1L.
- Therefore, the volume of water required for dilution is 0.1 liters.
Given:
- Initial concentration of the H3PO4 solution (C1) = 0.5M
- Initial volume of the H3PO4 solution (V1) = 20ml
- Final concentration of the diluted H3PO4 solution (C2) = 0.1N
Formula:
The formula to calculate the volume of water required for dilution is:
V2 = (C1 * V1) / C2
Calculations:
Substituting the given values in the formula:
V2 = (0.5M * 20ml) / 0.1N
Conversion of units:
Since the concentration is given in moles per liter (M) and the volume is given in milliliters (ml), we need to convert the volume to liters.
V2 = (0.5M * 0.02L) / 0.1N
V2 = 0.01L / 0.1N
V2 = 0.1L
Result:
The volume of water required for dilution is 0.1 liters.
Explanation:
- The given H3PO4 solution has an initial concentration of 0.5M and a volume of 20ml.
- We need to dilute this solution to obtain a final concentration of 0.1N.
- To calculate the volume of water required for dilution, we use the formula V2 = (C1 * V1) / C2, where V2 is the volume of water required, C1 is the initial concentration, V1 is the initial volume, and C2 is the final concentration.
- Substituting the given values, we get V2 = (0.5M * 20ml) / 0.1N.
- Since the concentration is in moles per liter (M) and the volume is in milliliters (ml), we need to convert the volume to liters by dividing it by 1000 (1L = 1000ml).
- After converting the volume to liters, we get V2 = (0.5M * 0.02L) / 0.1N.
- Simplifying the equation, we get V2 = 0.01L / 0.1N = 0.1L.
- Therefore, the volume of water required for dilution is 0.1 liters.
Community Answer
0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. T...
We have a formula relating normality and volume of the solution.
N1V1=N2V2
N1 and V1 are the normality and volume before dilution.
N2 and V2 are the normality and volume after dilution.
Normality (N) = nf × M
n-f is the n-factor and M represents molarity.
For H3PO4, nf = 3
therefore on substituting the values, we get
3×0.5×20 = 0.1×V
V=300ml
Do not confuse V with the volume required for dilution.
Volume required for dilution=300 - 20 = 280 ml
Hope so this is right, if not pls do convey!!
N1V1=N2V2
N1 and V1 are the normality and volume before dilution.
N2 and V2 are the normality and volume after dilution.
Normality (N) = nf × M
n-f is the n-factor and M represents molarity.
For H3PO4, nf = 3
therefore on substituting the values, we get
3×0.5×20 = 0.1×V
V=300ml
Do not confuse V with the volume required for dilution.
Volume required for dilution=300 - 20 = 280 ml
Hope so this is right, if not pls do convey!!
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0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. The volume of water required for this dilution is.?
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0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. The volume of water required for this dilution is.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. The volume of water required for this dilution is.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. The volume of water required for this dilution is.?.
0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. The volume of water required for this dilution is.? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. The volume of water required for this dilution is.? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.5M , 20ml H3PO4 solution is diluted to obtain 0.1N H3P04 solution. The volume of water required for this dilution is.?.
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