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Directions: 
In a locality having 1500  households, 1000 watch Zee TV, 300 watch NDTV and 750 watch Star Plus.
Based on this information answer the questions that follow:
The minimum number of households watching Zee TV and Star Plus is:
  • a)
    300
  • b)
    250
  • c)
    275
  • d)
    350
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Directions:In alocality having 1500households,1000watchZeeTV,300 watch...
If we try to consider each of the households watching Zee TV and   StarPlus as independent of  each   other, we would get a total of 1000 + 750 = 1750 households.However, wehave a totalof only1500 householdsi the locality and hence, there has to be a minimum interference of atleast 250 households whowould  be watching both Zee TV and Star Plus. Hence, the answer to this question is 250.
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Directions:In alocality having 1500households,1000watchZeeTV,300 watch...
Minimum Number of Households Watching ZeeTV and StarPlus

Given:
Total number of households = 1500
Number of households watching ZeeTV = 1000
Number of households watching NDTV = 300
Number of households watching StarPlus = 750

To find the minimum number of households watching ZeeTV and StarPlus, we need to determine the overlapping households between ZeeTV and StarPlus.

Method 1: Using the Inclusion-Exclusion Principle

The inclusion-exclusion principle states that if we want to count the number of elements in the union of multiple sets, we need to subtract the number of elements in the intersection of each pair of sets.

In this case, we want to count the number of households watching both ZeeTV and StarPlus. We can find this by subtracting the number of households watching only ZeeTV and the number of households watching only StarPlus from the total number of households.

Step 1: Find the number of households watching only ZeeTV:
Number of households watching only ZeeTV = Total households watching ZeeTV - Number of households watching ZeeTV and NDTV
Number of households watching only ZeeTV = 1000 - (1000 - 750)
Number of households watching only ZeeTV = 750

Step 2: Find the number of households watching only StarPlus:
Number of households watching only StarPlus = Total households watching StarPlus - Number of households watching ZeeTV and StarPlus
Number of households watching only StarPlus = 750 - (750 - 0)
Number of households watching only StarPlus = 0

Step 3: Find the number of households watching both ZeeTV and StarPlus:
Number of households watching both ZeeTV and StarPlus = Total households - (Number of households watching only ZeeTV + Number of households watching only StarPlus)
Number of households watching both ZeeTV and StarPlus = 1500 - (750 + 0)
Number of households watching both ZeeTV and StarPlus = 750

Therefore, the minimum number of households watching ZeeTV and StarPlus is 750.

Method 2: Using Venn Diagram

Alternatively, we can visualize the problem using a Venn diagram.

Step 1: Draw a rectangle to represent the total number of households (1500).

Step 2: Draw a circle to represent the households watching ZeeTV (1000) and shade it.

Step 3: Draw another circle to represent the households watching StarPlus (750) and shade it.

Step 4: Find the overlapping region between the two circles, which represents the households watching both ZeeTV and StarPlus. Count the number of households in this region.

In this case, the overlapping region represents 750 households.

Therefore, the minimum number of households watching ZeeTV and StarPlus is 750.

Conclusion

- The minimum number of households watching ZeeTV and StarPlus is 750, which is the number of households in the overlapping region between the two sets.
- This can be determined using the inclusion-exclusion principle or by visualizing the problem using a Venn diagram.
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Directions:In alocality having 1500households,1000watchZeeTV,300 watch NDTV and750watchStarPlus.Basedonthis informationanswerthequestionsthatfollow:TheminimumnumberofhouseholdswatchingZeeTVandStarPlusis:a)300b)250c)275d)350Correct answer is option 'B'. Can you explain this answer?
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