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A particle is moving on a straight line x y=2 Its angular momentum about origin is L=3t 2 (kgm^2s^-1).Find the force acting on the particle at t=2s (x and y are in metre) 1)3/√2N 2)3N 3)3√2N 4)√2N?
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A particle is moving on a straight line x y=2 Its angular momentum abo...
Given:
- The particle is moving on a straight line y = 2.
- The angular momentum of the particle about the origin is L = 3t^2 (kgm^2s^-1).
- The time at which we need to find the force acting on the particle is t = 2s.
To find:
The force acting on the particle at t = 2s.
Explanation:
1. Angular Momentum:
The angular momentum of a particle about a point O is given by the cross product of its position vector r and linear momentum vector p, defined as L = r x p.
In this case, the particle is moving on a straight line, so its position vector r is parallel to the line y = 2. Since the origin is on this line, the position vector r will pass through the origin. Therefore, the angular momentum L is given by L = r x p = r * p, as the cross product of parallel vectors is zero.
Given that L = 3t^2 (kgm^2s^-1), we can write L = r * p = 3t^2. Since r passes through the origin, r = 0 (position vector at the origin).
Therefore, p = L/r = 3t^2/0, which is undefined. This means that the linear momentum of the particle is undefined at t = 2s.
2. Force:
Since the linear momentum is undefined, we cannot directly calculate the force acting on the particle at t = 2s using Newton's second law (F = dp/dt).
Therefore, we cannot determine the force acting on the particle at t = 2s based on the given information.
Answer:
The force acting on the particle at t = 2s cannot be determined from the given information.
Community Answer
A particle is moving on a straight line x y=2 Its angular momentum abo...
Yeh xy=6 hai ya x+y hai
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A particle is moving on a straight line x y=2 Its angular momentum about origin is L=3t 2 (kgm^2s^-1).Find the force acting on the particle at t=2s (x and y are in metre) 1)3/√2N 2)3N 3)3√2N 4)√2N?
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