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Two pipes A and B can fill a tank in 10 hrs and 40 hrs respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?
- a)8 hours
- b)6 hours
- c)4 hours
- d)2 hours
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
Two pipes A and B can fill a tank in 10 hrs and 40 hrs respectively. I...
Pipe A can fill 1/10 of the tank in 1 hr
Pipe B can fill 1/40 of the tank in 1 hr
Pipe A and B together can fill 1/10 + 1/40 = 1/8 of the tank in 1 hr
i.e., Pipe A and B together can fill the tank in 8 hours
Pipe B can fill 1/40 of the tank in 1 hr
Pipe A and B together can fill 1/10 + 1/40 = 1/8 of the tank in 1 hr
i.e., Pipe A and B together can fill the tank in 8 hours
Most Upvoted Answer
Two pipes A and B can fill a tank in 10 hrs and 40 hrs respectively. I...
To solve this problem, we need to understand the concept of work done.
Work done is defined as the product of the rate at which work is done and the time taken to do the work. In this case, the work done is filling the tank completely.
Let's consider the rate at which each pipe fills the tank:
- Pipe A fills the tank in 10 hours, so its rate is 1/10 of the tank per hour.
- Pipe B fills the tank in 40 hours, so its rate is 1/40 of the tank per hour.
Now, when both pipes are opened simultaneously, their rates are added together to fill the tank:
- Rate of pipe A + Rate of pipe B = 1/10 + 1/40 = 4/40 + 1/40 = 5/40 = 1/8 of the tank per hour.
Now, we can calculate the time taken to fill the tank using the concept of work done:
- Time taken = 1 / (Rate of filling the tank)
- Time taken = 1 / (1/8) = 8 hours.
Hence, the correct answer is option A) 8 hours.
Work done is defined as the product of the rate at which work is done and the time taken to do the work. In this case, the work done is filling the tank completely.
Let's consider the rate at which each pipe fills the tank:
- Pipe A fills the tank in 10 hours, so its rate is 1/10 of the tank per hour.
- Pipe B fills the tank in 40 hours, so its rate is 1/40 of the tank per hour.
Now, when both pipes are opened simultaneously, their rates are added together to fill the tank:
- Rate of pipe A + Rate of pipe B = 1/10 + 1/40 = 4/40 + 1/40 = 5/40 = 1/8 of the tank per hour.
Now, we can calculate the time taken to fill the tank using the concept of work done:
- Time taken = 1 / (Rate of filling the tank)
- Time taken = 1 / (1/8) = 8 hours.
Hence, the correct answer is option A) 8 hours.
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Community Answer
Two pipes A and B can fill a tank in 10 hrs and 40 hrs respectively. I...
To determine the time it takes to fill the tank when both pipes A and B are opened simultaneously, we need to calculate their combined rate of filling the tank.
Let's denote the rate at which pipe A can fill the tank as A_rate (in tanks per hour) and the rate at which pipe B can fill the tank as B_rate (in tanks per hour).
Given:
● Pipe A can fill the tank in 10 hours, so its rate is 1/10 tanks per hour (1 tank in 10 hours).
● Pipe B can fill the tank in 40 hours, so its rate is 1/40 tanks per hour (1 tank in 40 hours).
When both pipes are opened simultaneously, their rates of filling the tank are additive. Therefore, the combined rate is:
Combined_rate = A_rate + B_rate = 1/10 + 1/40 = 4/40 + 1/40 = 5/40 = 1/8 tanks per hour.
This means that when both pipes are opened, they can fill 1/8th of the tank in one hour.
To determine the time taken to fill the entire tank, we can calculate the reciprocal of the combined rate:
Time = 1 / Combined_rate = 1 / (1/8) = 8/1 = 8 hours.
Hence, the correct answer is option 'A) 8 hours' as it would take 8 hours to fill the tank when both pipes A and B are opened simultaneously.
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Two pipes A and B can fill a tank in 10 hrs and 40 hrs respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?a)8 hoursb)6 hoursc)4 hoursd)2 hoursCorrect answer is option 'A'. Can you explain this answer?
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