NEET Exam > NEET Questions > Two moles of monoatomic ideal gas at 60oC are...
Start Learning for Free
Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture is
- a)36oC
- b)44oC
- c)48oC
- d)72oC
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with...
Most Upvoted Answer
Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with...
Given: Two moles of monoatomic ideal gas at 60oC, one mole of another monoatomic ideal gas at 12oC, mixed adiabatically.
To find: The final temperature of the mixture.
Solution:
1. First, let's find the initial temperatures of the gases:
- Two moles of monoatomic ideal gas at 60oC have a total energy of E1 = (5/2)RT1, where R is the gas constant and T1 is the temperature in Kelvin.
- One mole of monoatomic ideal gas at 12oC has an energy of E2 = (3/2)RT2.
2. Next, let's find the total energy of the mixture before and after mixing:
- Before mixing, the total energy of the gases is E1 + E2.
- After mixing, the total energy remains the same since the process is adiabatic (i.e. no heat is exchanged with the surroundings).
3. Now, let's use the conservation of energy to find the final temperature of the mixture:
- E1 + E2 = (5/2)RTf + RTf, where Tf is the final temperature of the mixture in Kelvin.
- Simplifying the equation, we get E1 + E2 = (7/2)RTf.
- Substituting the values of E1, E2 and solving for Tf, we get Tf = 44oC.
Therefore, the final temperature of the mixture is 44oC, which is option B.
To find: The final temperature of the mixture.
Solution:
1. First, let's find the initial temperatures of the gases:
- Two moles of monoatomic ideal gas at 60oC have a total energy of E1 = (5/2)RT1, where R is the gas constant and T1 is the temperature in Kelvin.
- One mole of monoatomic ideal gas at 12oC has an energy of E2 = (3/2)RT2.
2. Next, let's find the total energy of the mixture before and after mixing:
- Before mixing, the total energy of the gases is E1 + E2.
- After mixing, the total energy remains the same since the process is adiabatic (i.e. no heat is exchanged with the surroundings).
3. Now, let's use the conservation of energy to find the final temperature of the mixture:
- E1 + E2 = (5/2)RTf + RTf, where Tf is the final temperature of the mixture in Kelvin.
- Simplifying the equation, we get E1 + E2 = (7/2)RTf.
- Substituting the values of E1, E2 and solving for Tf, we get Tf = 44oC.
Therefore, the final temperature of the mixture is 44oC, which is option B.
Free Test
FREE
| Start Free Test |
Community Answer
Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with...
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer?
Question Description
Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer?.
Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer?.
Solutions for Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Two moles of monoatomic ideal gas at 60oC are mixed adiabatically with one mole of another monoatomic ideal gas at 12oC. The final temperature of the mixture isa)36oCb)44oCc)48oCd)72oCCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup