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Consider reaction cl2 2 b r minus give due to CL minus br2 the EMF of the cell when CL minus equals to B are two equals to B A minus equals to 0.01 molar and cl2 gas at 1 ATM pressure will be when the inner for the above reaction is 0.29 volt?
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Consider reaction cl2 2 b r minus give due to CL minus br2 the EMF...
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Consider reaction cl2 2 b r minus give due to CL minus br2 the EMF...
Introduction:
In this reaction, chlorine gas (Cl2) reacts with bromide ions (Br-) to form chloride ions (Cl-) and bromine gas (Br2). The aim is to calculate the electromotive force (EMF) of the cell when the concentrations of Cl-, Br-, and Br2 are known.

Given information:
- The reaction is Cl2 + 2Br- -> 2Cl- + Br2
- Cl- concentration (CB) = Br- concentration (CA) = 0.01 M
- EMF of the cell (Ecell) = 0.29 V

Calculating the standard cell potential (E°cell):
Standard cell potential (E°cell) can be calculated using the Nernst equation:
E°cell = E°cathode - E°anode

Identifying the cathode and anode:
In this reaction, Cl- is being reduced to Cl2, which means Cl- acts as the cathode.
Br- is being oxidized to Br2, which means Br- acts as the anode.

Writing half-reactions:
Cathode (reduction half-reaction):
2Cl- -> Cl2 + 2e-

Anode (oxidation half-reaction):
2Br- -> Br2 + 2e-

Calculating the standard reduction potentials (E°):
Using standard reduction potentials table, we find:
E°cathode = 1.36 V
E°anode = 1.07 V

Calculating E°cell:
E°cell = E°cathode - E°anode
E°cell = 1.36 V - 1.07 V
E°cell = 0.29 V (matches the given value)

Calculating the concentration of Br2:
Using the Nernst equation:
Ecell = E°cell - (0.0592/n) * log(Q)

Where n is the number of electrons transferred and Q is the reaction quotient.

Calculating Q:
Q = [Cl-]^2 / [Br-]^2

Given that CB = CA = 0.01 M:
Q = (0.01)^2 / (0.01)^2
Q = 1

Using the Nernst equation to find the concentration of Br2:
Ecell = E°cell - (0.0592/n) * log(Q)
0.29 = 0 - (0.0592/2) * log(1)

Simplifying the equation:
0.29 = -0.0296 * log(1)
log(1) = 0

Calculating the concentration of Br2:
0.29 = -0.0296 * 0
0.29 = 0

Conclusion:
The calculated concentration of Br2 is 0. Since the calculated value does not match the given value, there may be an error in the given information or an error in the calculations. Please double-check the values and calculations to ensure accuracy.
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Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. Nucleophilic substitution will be fastest in case of

Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. SN1 reaction will be fastest in case of

Read the passage given below and answer the following questions:Nucleophilic substitution reaction of haloalkane can be conducted according to both SN1 and SN2 mechanisms. However, which mechanism it is based on is related to such factors as the structure of haloalkane, and properties of leaving group, nucleophilic reagent and solvent. Influences of halogen: No matter which mechanism the nucleophilic substitution reaction is based on, the leaving group always leave the central carbon atom with electron pair. This is just the opposite of the situation that nucleophilic reagent attacks the central carbon atom with electron pair. Therefore, the weaker the alkalinity of leaving group is , the more stable the anion formed is and it will be more easier for the leaving group to leave the central carbon atom; that is to say, the reactant is more easier to be substituted. The alkalinity order of halogen ion is I− < Br− < Cl− < F− and the order of their leaving tendency should be I− > Br− > Cl− > F−. Therefore, in four halides with the same alkyl and different halogens, the order of substitution reaction rate is RI > RBr > RCl > RF. In addition, if the leaving group is very easy to leave, many carbocation intermediates are generated in the reaction and the reaction is based on SN1 mechanism. If the leaving group is not easy to leave, the reaction is based on SN2 mechanism. Influences of solvent polarity: In SN1 reaction, the polarity of the system increases from the reactant to the transition state, because polar solvent has a greater stabilizing effect on the transition state than the reactant, thereby reduce activation energy and accelerate the reaction. In SN2 reaction, the polarity of the system generally does not change from the reactant to the transition state and only charge dispersion occurs. At this time, polar solvent has a great stabilizing effect on Nu than the transition state, thereby increasing activation energy and slow down the reaction rate. For example, the decomposition rate (SN1) of tertiary chlorobutane in 25° water (dielectric constant 79) is 300000 times faster than in ethanol (dielectric constant 24). The reaction rate (SN2) of 2-bromopropane and NaOH in ethanol containing 40% water is twice slower than in absolute ethanol. In a word, the level of solvent polarity has influence on both SN1 and SN2 reactions, but with different results. Generally speaking, weak polar solvent is favorable for SN2 reaction, while strong polar solvent is favorable for SN1 reaction, because only under the action of polar solvent can halogenated hydrocarbon dissociate into carbocation and halogen ion and solvents with a strong polarity is favorable for solvation of carbocation, increasing its stability. Generally speaking, the substitution reaction of tertiary haloalkane is based on SN1 mechanism in solvents with a strong polarity (for example, ethanol containing water).Q. SN1 reaction will be fastest in which of the following solvents?

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Consider reaction cl2 2 b r minus give due to CL minus br2 the EMF of the cell when CL minus equals to B are two equals to B A minus equals to 0.01 molar and cl2 gas at 1 ATM pressure will be when the inner for the above reaction is 0.29 volt?
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Consider reaction cl2 2 b r minus give due to CL minus br2 the EMF of the cell when CL minus equals to B are two equals to B A minus equals to 0.01 molar and cl2 gas at 1 ATM pressure will be when the inner for the above reaction is 0.29 volt? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Consider reaction cl2 2 b r minus give due to CL minus br2 the EMF of the cell when CL minus equals to B are two equals to B A minus equals to 0.01 molar and cl2 gas at 1 ATM pressure will be when the inner for the above reaction is 0.29 volt? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider reaction cl2 2 b r minus give due to CL minus br2 the EMF of the cell when CL minus equals to B are two equals to B A minus equals to 0.01 molar and cl2 gas at 1 ATM pressure will be when the inner for the above reaction is 0.29 volt?.
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