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A sum of money invested at simple interest triples itself in 8 years at simple interest. Find in how many years will it become 8 times itself at the same rate?
  • a)
    24 years
  • b)
    28 years
  • c)
    30 years
  • d)
    21 years
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A sum of money invested at simple interest triples itself in 8 years a...
In 8 years, the interest earned = 200% Thus, per year interest rate = 200/8 = 25% To become 8 times we need a 700% increase 700/25 = 28 years.
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Most Upvoted Answer
A sum of money invested at simple interest triples itself in 8 years a...
Given:
- A sum of money triples itself in 8 years at simple interest.

To find:
- In how many years will it become 8 times itself at the same rate?

Solution:
Let's assume the sum of money to be x.
After 8 years at simple interest, the sum of money becomes 3x.
Let the required time be y years.
After y years at the same rate, the sum of money becomes 8x.

Formula:
Simple Interest = (P * R * T)/100

Calculation:
Using the formula of Simple Interest, we can find the rate of interest.

For the first case:
3x = x + (x * R * 8)/100
2x = (x * R * 8)/100
R = 25%

For the second case:
8x = x + (x * 25 * y)/100
7x = (x * 25 * y)/100
y = 28 years

Therefore, the sum of money will become 8 times itself after 28 years at the same rate.

Answer: Option B) 28 years
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A sum of money invested at simple interest triples itself in 8 years at simple interest. Find in how many years will it become 8 times itself at the same rate?a)24 yearsb)28 yearsc)30 yearsd)21 yearsCorrect answer is option 'B'. Can you explain this answer?
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