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The odds in favour of standing first of three students Amit, Vikas and Vivek appearing at an examination are 1 : 2. 2 : 5 and 1 : 7 respectively. What is the probability that either of them will stand first (assume that a tie for the first place is not possible).
  • a)
    168/178
  • b)
    124/168
  • c)
    5/168
  • d)
    125/168
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The odds in favour of standing first of three students Amit, Vikas and...
P (Amit) = 1/3
P (Vikas) = 2/7
P (Vivek) = 1/8.
Required Probability = 1/3 + 2/7 + 1/8 = 125/168.
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Most Upvoted Answer
The odds in favour of standing first of three students Amit, Vikas and...
To find the probability that either Amit, Vikas, or Vivek will stand first, we need to consider the individual probabilities of each student standing first and then add them together.

Given that the odds in favor of Amit standing first are 1:2, we can determine the probability as follows:

Probability of Amit standing first = 1 / (1 + 2) = 1/3

Similarly, the probability of Vikas standing first is:

Probability of Vikas standing first = 2 / (2 + 5) = 2/7

And the probability of Vivek standing first is:

Probability of Vivek standing first = 1 / (1 + 7) = 1/8

Now, since the events of Amit, Vikas, and Vivek standing first are mutually exclusive (meaning only one of them can stand first), we can add the probabilities together to find the probability that either of them will stand first:

Probability = Probability of Amit standing first + Probability of Vikas standing first + Probability of Vivek standing first
= 1/3 + 2/7 + 1/8
= (56 + 24 + 21) / (3 * 7 * 8)
= 101 / 168

So, the correct answer is option D, 125/168.
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The odds in favour of standing first of three students Amit, Vikas and Vivek appearing at an examination are 1 : 2. 2 : 5 and 1 : 7 respectively. What is the probability that either of them will stand first (assume that a tie for the first place is not possible).a)168/178b)124/168c)5/168d)125/168Correct answer is option 'D'. Can you explain this answer?
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