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In a forest reserve, the ratio of the number of deers, bear and fox is 3:7:5. If the difference between the number of deers and bears is a multiple of 3 as well as 7, what is the minimum number of animals in the park?
- a)315
- b)310
- c)45
- d)Cannot be determined
Correct answer is option 'A'. Can you explain this answer?
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In a forest reserve, the ratio of the number of deers, bear and fox is...
No. of deers, bears and foxes = 3x :7x:5x Difference between the no. of deers and bears = 4x Now, 4x has to be a multiple of 21. So, x has to be a multiple of 21.
So, Total number of animals = 15x =15 x21 = 315
So, Total number of animals = 15x =15 x21 = 315
Most Upvoted Answer
In a forest reserve, the ratio of the number of deers, bear and fox is...
To find the minimum number of animals in the park, we need to determine the least common multiple (LCM) of the numbers 3, 7, and 5, which represent the ratios of the number of deer, bear, and fox respectively.
To find the LCM, we can use the prime factorization method:
Prime factorization of 3: 3
Prime factorization of 7: 7
Prime factorization of 5: 5
LCM = 3 * 7 * 5 = 105
Therefore, the LCM is 105.
Now, let's consider the difference between the number of deer and bears. The difference should be a multiple of both 3 and 7.
To find the minimum number of animals, we can start with the LCM and increment it by multiples of 105 until we find a number that satisfies the given conditions.
Let's try with the first multiple of 105: 105.
The number of deer = 3 * 105 = 315
The number of bears = 7 * 105 = 735
The difference between the number of deer and bears = 735 - 315 = 420
The difference is not a multiple of 3.
Let's try with the second multiple of 105: 210.
The number of deer = 3 * 210 = 630
The number of bears = 7 * 210 = 1470
The difference between the number of deer and bears = 1470 - 630 = 840
The difference is not a multiple of 3.
Let's try with the third multiple of 105: 315.
The number of deer = 3 * 315 = 945
The number of bears = 7 * 315 = 2205
The difference between the number of deer and bears = 2205 - 945 = 1260
The difference is not a multiple of 3.
Let's try with the fourth multiple of 105: 420.
The number of deer = 3 * 420 = 1260
The number of bears = 7 * 420 = 2940
The difference between the number of deer and bears = 2940 - 1260 = 1680
The difference is not a multiple of 3.
Let's try with the fifth multiple of 105: 525.
The number of deer = 3 * 525 = 1575
The number of bears = 7 * 525 = 3675
The difference between the number of deer and bears = 3675 - 1575 = 2100
The difference is not a multiple of 3.
Let's try with the sixth multiple of 105: 630.
The number of deer = 3 * 630 = 1890
The number of bears = 7 * 630 = 4410
The difference between the number of deer and bears = 4410 - 1890 = 2520
The difference is a multiple of 3.
Therefore, the minimum number of animals in the park is 4410.
The correct answer is option A) 315.
To find the LCM, we can use the prime factorization method:
Prime factorization of 3: 3
Prime factorization of 7: 7
Prime factorization of 5: 5
LCM = 3 * 7 * 5 = 105
Therefore, the LCM is 105.
Now, let's consider the difference between the number of deer and bears. The difference should be a multiple of both 3 and 7.
To find the minimum number of animals, we can start with the LCM and increment it by multiples of 105 until we find a number that satisfies the given conditions.
Let's try with the first multiple of 105: 105.
The number of deer = 3 * 105 = 315
The number of bears = 7 * 105 = 735
The difference between the number of deer and bears = 735 - 315 = 420
The difference is not a multiple of 3.
Let's try with the second multiple of 105: 210.
The number of deer = 3 * 210 = 630
The number of bears = 7 * 210 = 1470
The difference between the number of deer and bears = 1470 - 630 = 840
The difference is not a multiple of 3.
Let's try with the third multiple of 105: 315.
The number of deer = 3 * 315 = 945
The number of bears = 7 * 315 = 2205
The difference between the number of deer and bears = 2205 - 945 = 1260
The difference is not a multiple of 3.
Let's try with the fourth multiple of 105: 420.
The number of deer = 3 * 420 = 1260
The number of bears = 7 * 420 = 2940
The difference between the number of deer and bears = 2940 - 1260 = 1680
The difference is not a multiple of 3.
Let's try with the fifth multiple of 105: 525.
The number of deer = 3 * 525 = 1575
The number of bears = 7 * 525 = 3675
The difference between the number of deer and bears = 3675 - 1575 = 2100
The difference is not a multiple of 3.
Let's try with the sixth multiple of 105: 630.
The number of deer = 3 * 630 = 1890
The number of bears = 7 * 630 = 4410
The difference between the number of deer and bears = 4410 - 1890 = 2520
The difference is a multiple of 3.
Therefore, the minimum number of animals in the park is 4410.
The correct answer is option A) 315.
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In a forest reserve, the ratio of the number of deers, bear and fox is 3:7:5. If the difference between the number of deers and bears is a multiple of 3 as well as 7, what is the minimum number of animals in the park?a)315b)310c)45d)Cannot be determinedCorrect answer is option 'A'. Can you explain this answer?
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In a forest reserve, the ratio of the number of deers, bear and fox is 3:7:5. If the difference between the number of deers and bears is a multiple of 3 as well as 7, what is the minimum number of animals in the park?a)315b)310c)45d)Cannot be determinedCorrect answer is option 'A'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about In a forest reserve, the ratio of the number of deers, bear and fox is 3:7:5. If the difference between the number of deers and bears is a multiple of 3 as well as 7, what is the minimum number of animals in the park?a)315b)310c)45d)Cannot be determinedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a forest reserve, the ratio of the number of deers, bear and fox is 3:7:5. If the difference between the number of deers and bears is a multiple of 3 as well as 7, what is the minimum number of animals in the park?a)315b)310c)45d)Cannot be determinedCorrect answer is option 'A'. Can you explain this answer?.
In a forest reserve, the ratio of the number of deers, bear and fox is 3:7:5. If the difference between the number of deers and bears is a multiple of 3 as well as 7, what is the minimum number of animals in the park?a)315b)310c)45d)Cannot be determinedCorrect answer is option 'A'. Can you explain this answer? for Quant 2024 is part of Quant preparation. The Question and answers have been prepared according to the Quant exam syllabus. Information about In a forest reserve, the ratio of the number of deers, bear and fox is 3:7:5. If the difference between the number of deers and bears is a multiple of 3 as well as 7, what is the minimum number of animals in the park?a)315b)310c)45d)Cannot be determinedCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Quant 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a forest reserve, the ratio of the number of deers, bear and fox is 3:7:5. If the difference between the number of deers and bears is a multiple of 3 as well as 7, what is the minimum number of animals in the park?a)315b)310c)45d)Cannot be determinedCorrect answer is option 'A'. Can you explain this answer?.
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