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There are three vessels A, B and C having a mixture of milk and water. Concentration of milk in the vessels is C1? C2 and C3 respectively. When a part of vessel A is replaced with the mixture in vessel B, then the concentration of milk in the final mixture is less than Cr However, when vessels B and C are mixed in the ratio of 1:1, then the quantity of milk in the final mixture is double than the quantity of milk in the vessel B. Which of the vessels is having the mixture of maximum concentration of milk?
  • a)
    A
  • b)
    B
  • c)
    C
  • d)
    Cannot be determined
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
There are three vessels A, B and C having a mixture of milk and water....
When a part of vessel A is replaced with the mixture in vessel B, then the concentration of milk in the final mixture is less than C- I t im p lie s th a t C1 > C2 When vessels B and C are mixed in the ratio 1:1, then the quantity of milk in the final mixture is double than the quantity of milk in the vessel B - It implies that C2 = C3
Hence C1 is greatest
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Most Upvoted Answer
There are three vessels A, B and C having a mixture of milk and water....
Given information:
- Vessel A has concentration of milk C1, vessel B has concentration of milk C2, and vessel C has concentration of milk C3.
- When a part of vessel A is replaced with the mixture in vessel B, the concentration of milk in the final mixture is less than Cr.
- When vessels B and C are mixed in the ratio of 1:1, the quantity of milk in the final mixture is double than the quantity of milk in vessel B.

To find: Which vessel has the mixture of maximum concentration of milk?

Let's analyze the given information step by step.

1. Concentration of milk after replacing a part of vessel A with mixture from vessel B:
- Let's assume that x units are replaced from vessel A with mixture from vessel B.
- The concentration of milk in vessel A after the replacement would be (C1 - (x/C1)) since x units are replaced.
- The concentration of milk in vessel B remains C2.
- The concentration of milk in the final mixture can be calculated using the formula:
C_final = (C1 - (x/C1) + (x/C1) * C2)
- According to the given information, C_final < />

2. Quantity of milk after mixing vessels B and C in the ratio of 1:1:
- Let's assume that y units are taken from vessel B and y units are taken from vessel C for mixing.
- The quantity of milk in vessel B is y * C2.
- The quantity of milk in vessel C is y * C3.
- The quantity of milk in the final mixture is (y * C2) + (y * C3).
- According to the given information, the quantity of milk in the final mixture is double the quantity of milk in vessel B.
Therefore, (y * C2) + (y * C3) = 2 * (y * C2).

From the above analysis, we can conclude that:
- The concentration of milk in the final mixture after replacing a part of vessel A with mixture from vessel B is less than Cr.
- The quantity of milk in the final mixture after mixing vessels B and C in the ratio of 1:1 is double the quantity of milk in vessel B.

Since the question asks for the vessel with the maximum concentration of milk, we can conclude that vessel A (option A) has the mixture with the maximum concentration of milk, as it is the only vessel involved in the first scenario. The concentrations of milk in vessels B and C are not directly compared in the given information.

Therefore, the correct answer is option A.
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There are three vessels A, B and C having a mixture of milk and water. Concentration of milk in the vessels is C1? C2 and C3 respectively. When a part of vessel A is replaced with the mixture in vessel B, then the concentration of milk in the final mixture is less than Cr However, when vessels B and C are mixed in the ratio of 1:1, then the quantity of milk in the final mixture is double than the quantity of milk in the vessel B. Which of the vessels is having the mixture of maximum concentration of milk?a)Ab)Bc)Cd)Cannot be determinedCorrect answer is option 'A'. Can you explain this answer?
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