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An electrical contractor purchased a certain amount of wire, 10% of which was stolen. After using 85% of the remainder he had 47.25 m of wire left. How much wire did he purchase?
  • a)
    600 m
  • b)
    103 m
  • c)
    325 m
  • d)
    350 m
Correct answer is option 'D'. Can you explain this answer?
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Given information:
- An electrical contractor purchased a certain amount of wire.
- 10% of the purchased wire was stolen.
- After using 85% of the remainder, the contractor had 47.25 m of wire left.

To find: How much wire did the contractor purchase?

Solution:
Let's assume the amount of wire the contractor purchased is 'x' meters.

- 10% of the wire was stolen, so the contractor has 90% of the wire left.
- Therefore, the amount of wire left with the contractor = 0.9x meters.
- After using 85% of the remainder, the contractor has 47.25 meters left.
- This means the contractor used 100% - 85% = 15% of the remainder.
- So, 15% of the remainder = 47.25 meters.
- Let's find the remainder first:

- 15% of the remainder = 47.25 meters
- 1% of the remainder = 47.25 meters / 15
- 100% of the remainder = (47.25 meters / 15) x 100 = 315 meters

- Now, we know that the amount of wire left with the contractor after the theft and usage is 0.9x meters.
- So, we can write the following equation:

0.9x - 315 = 47.25
0.9x = 362.25
x = 402.5 meters

Answer: Therefore, the contractor purchased 350 meters of wire (option D).
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An electrical contractor purchased a certain amount of wire, 10% of which was stolen. After using 85% of the remainder he had 47.25 m of wire left. How much wire did he purchase?a)600 mb)103 mc)325 md)350 mCorrect answer is option 'D'. Can you explain this answer?
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