Two pipes A and B can fill a tank in 20 hours...
Two pipes A and B can fill a tank in 20 hours and 24 hours respectively, if the two pipes opened at 5 am in the morning, then at what time the pipe A should be closed to completely fill the tank exactly at 5 in the evening?
• a)
3 pm
• b)
2 pm
• c)
4 pm
• d)
1 pm
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Two pipes A and B can fill a tank in 20 hours and 24 hours respectivel...
Two pipes A and B can fill a tank in 20 hours and 24 hours respectively,
Let total work be 120 units,
As B worked for all the time,
⇒ Work done by B in 12 hours = 120/24 × 12 = 60 units
Remaining work was done by A,
⇒ A would take 60 × 20/120 hours = 10 hours
∴ A should be closed at 3 pm.
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Two pipes A and B can fill a tank in 20 hours and 24 hours respectivel...
To solve this problem, we need to find the time it takes for pipe A to fill the tank and then subtract that time from the total time available (from 5 am to 5 pm) to determine when pipe A should be closed.

Let's calculate the time it takes for pipe A to fill the tank:

- Pipe A can fill the tank in 20 hours.
- Therefore, in 1 hour, pipe A can fill 1/20th of the tank.

Now let's calculate the time it takes for pipe B to fill the tank:

- Pipe B can fill the tank in 24 hours.
- Therefore, in 1 hour, pipe B can fill 1/24th of the tank.

Since both pipes are open from 5 am to 5 pm, we have a total of 12 hours available to fill the tank. Now we can calculate the amount of the tank filled by each pipe in 12 hours:

- Pipe A can fill (1/20) x 12 = 12/20 = 3/5 of the tank in 12 hours.
- Pipe B can fill (1/24) x 12 = 12/24 = 1/2 of the tank in 12 hours.

Since we want to completely fill the tank, the sum of the amounts filled by both pipes should be equal to 1.

- (3/5) + (1/2) = 6/10 + 5/10 = 11/10

Therefore, the combined fill rate of both pipes is greater than 1. This means that pipe A alone can fill the tank in less than 12 hours.

To find the exact time when pipe A should be closed, we need to calculate the time it takes for pipe A to fill the tank completely:

- Pipe A can fill 1/20th of the tank in 1 hour.
- Therefore, pipe A can fill the entire tank in 20 hours.

Since pipe A needs to be closed at 5 pm, we need to subtract 20 hours from the total time available (12 hours):

- 12 - 20 = -8

As the result is negative, it means that pipe A should be closed 8 hours before 5 pm, which is 9 am.

Therefore, pipe A should be closed at 9 am in order to completely fill the tank by 5 pm.
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Two pipes A and B can fill a tank in 20 hours and 24 hours respectively, if the two pipes opened at 5 am in the morning, then at what time the pipe A should be closed to completely fill the tank exactly at 5 in the evening?a)3 pmb)2 pmc)4 pmd)1 pmCorrect answer is option 'A'. Can you explain this answer? for SSC JE 2024 is part of SSC JE preparation. The Question and answers have been prepared according to the SSC JE exam syllabus. Information about Two pipes A and B can fill a tank in 20 hours and 24 hours respectively, if the two pipes opened at 5 am in the morning, then at what time the pipe A should be closed to completely fill the tank exactly at 5 in the evening?a)3 pmb)2 pmc)4 pmd)1 pmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for SSC JE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two pipes A and B can fill a tank in 20 hours and 24 hours respectively, if the two pipes opened at 5 am in the morning, then at what time the pipe A should be closed to completely fill the tank exactly at 5 in the evening?a)3 pmb)2 pmc)4 pmd)1 pmCorrect answer is option 'A'. Can you explain this answer?.
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