The year next to 2003 will have the same calendar as that of the year ...
Given year 2003, when divided by 4 leaves a remainder of 3.
NOTE: When remainder is 3, 11 is added to the given year to get the result.
So, 2003 + 11 = 2014
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The year next to 2003 will have the same calendar as that of the year ...
Explanation:
To determine which year will have the same calendar as 2003, we need to consider the leap years and the number of days in each month. The calendar repeats itself every 28 years, so we can start by finding the remainder when 2003 is divided by 28.
Step 1: Finding the remainder
2003 ÷ 28 = 71 remainder 15
This means that the calendar in the year 2003 will be the same as the calendar in the year that is 15 years after a multiple of 28.
Step 2: Finding the year that is 15 years after a multiple of 28
To find the year that is 15 years after a multiple of 28, we can subtract 15 from a multiple of 28 until we find the closest year.
Starting with the current year, 2003:
2003 - 15 = 1988 (not a multiple of 28)
1988 - 15 = 1973 (not a multiple of 28)
1973 - 15 = 1958 (not a multiple of 28)
1958 - 15 = 1943 (not a multiple of 28)
1943 - 15 = 1928 (a multiple of 28)
So, the closest year that is 15 years after a multiple of 28 is 1928.
Step 3: Determining the calendar of the year 1928
To determine the calendar of the year 1928, we need to consider the leap years and the number of days in each month.
1928 is a leap year because it is divisible by 4.
Key Point:
The calendar of a leap year repeats itself every 28 years.
So, the calendar of 1928 is the same as the calendar of 2003.
Conclusion:
Therefore, the year that has the same calendar as 2003 is 2014 (15 years after 1999, which is a multiple of 28).