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A spring balance is attached to the ceiling of a lift. A man hangs his bag in the spring and spring reads 49N, when the lift is stationary. If the lift moves downward with an acceleration of 5m/s2, the reading of the spring balance will be?
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A spring balance is attached to the ceiling of a lift. A man hangs his...
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A spring balance is attached to the ceiling of a lift. A man hangs his...
Analysis:
To find the reading of the spring balance when the lift moves downward with an acceleration of 5m/s2, we need to consider the forces acting on the bag in the lift.

Forces acting on the bag:
1. Weight (mg): The weight of the bag is the force due to gravity acting on it. It is given by the formula: weight = mass x acceleration due to gravity.

2. Tension (T): The tension in the spring balance is the force exerted by the spring to support the weight of the bag. It is equal in magnitude but opposite in direction to the weight of the bag.

3. Net force (Fnet): The net force acting on the bag is the difference between the tension and the weight. It is given by the formula: Fnet = T - mg.

Calculations:
Step 1: Calculate the weight of the bag when the lift is stationary.
Given: Reading of the spring balance = 49N
Since the reading of the spring balance is the tension in the spring, we can write T = 49N.
Let's assume the mass of the bag is m kg. Therefore, weight = mg.

Step 2: Calculate the weight of the bag when the lift is accelerating downward.
Given: Acceleration of the lift = 5m/s2
The weight of the bag when the lift is accelerating downward can be calculated using the formula: weight = mass x acceleration due to gravity.
Since the acceleration due to gravity is constant (approximately 9.8m/s2), the weight of the bag is equal to its mass multiplied by the acceleration due to gravity.

Step 3: Calculate the net force on the bag.
Using the formula Fnet = T - mg, we can calculate the net force acting on the bag.

Step 4: Calculate the reading of the spring balance when the lift is accelerating downward.
The reading of the spring balance is equal to the net force acting on the bag.

Explanation:
When the lift is stationary, the reading of the spring balance is equal to the weight of the bag. This is because the net force on the bag is zero when the lift is not moving. However, when the lift accelerates downward, an additional force acts on the bag due to its inertia. This force adds to the weight of the bag, resulting in a greater net force. As a result, the reading of the spring balance increases.

By calculating the net force on the bag and considering the additional force due to acceleration, we can determine the new reading of the spring balance when the lift is moving downward with an acceleration of 5m/s2.
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A spring balance is attached to the ceiling of a lift. A man hangs his bag in the spring and spring reads 49N, when the lift is stationary. If the lift moves downward with an acceleration of 5m/s2, the reading of the spring balance will be?
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A spring balance is attached to the ceiling of a lift. A man hangs his bag in the spring and spring reads 49N, when the lift is stationary. If the lift moves downward with an acceleration of 5m/s2, the reading of the spring balance will be? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A spring balance is attached to the ceiling of a lift. A man hangs his bag in the spring and spring reads 49N, when the lift is stationary. If the lift moves downward with an acceleration of 5m/s2, the reading of the spring balance will be? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A spring balance is attached to the ceiling of a lift. A man hangs his bag in the spring and spring reads 49N, when the lift is stationary. If the lift moves downward with an acceleration of 5m/s2, the reading of the spring balance will be?.
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