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An object of mass 100 gram is tied to one end of a string of 1 metre length it revolves around along a circular path of in a vertical plane its velocity is 2 metre per second when string makes an angle of 60 degree with the vertical the tension at this position will be ?
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An object of mass 100 gram is tied to one end of a string of 1 metre l...
Calculation of tension in the string


Given Data:


  • Mass of object (m) = 100 g = 0.1 kg

  • Length of string (l) = 1 m

  • Velocity of object (v) = 2 m/s

  • Angle made by string with vertical (θ) = 60°

  • Acceleration due to gravity (g) = 9.8 m/s²



Calculations:


  • First, let's find the centripetal force acting on the object:


    • Centripetal force (F) = (m * v²) / r

    • Here, r = l * sin(θ) (distance from center to the object)

    • So, F = (0.1 * 2²) / (1 * sin(60°))

    • Thus, F = 0.4 N


  • Next, let's find the weight of the object:


    • Weight (W) = m * g

    • So, W = 0.1 * 9.8

    • Thus, W = 0.98 N


  • Finally, let's find the tension in the string:


    • At the position when the string makes an angle of 60° with the vertical, the tension (T) in the string can be found using:

    • T - W * cos(θ) = F

    • So, T - 0.98 * cos(60°) = 0.4

    • Thus, T = 1.36 N




Answer:

The tension in the string at the position when the string makes an angle of 60° with the vertical is 1.36 N.
Community Answer
An object of mass 100 gram is tied to one end of a string of 1 metre l...
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An object of mass 100 gram is tied to one end of a string of 1 metre length it revolves around along a circular path of in a vertical plane its velocity is 2 metre per second when string makes an angle of 60 degree with the vertical the tension at this position will be ?
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