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Enzymes enhance the rate of reaction by
[2000]
  • a)
    forming a reactant-product complex
  • b)
    changing the equilibrium point of the reaction
  • c)
    combining with the product as soon as it is  formed
  • d)
    lowering the activation energy of the reaction 
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Enzymes enhance the rate of reaction by[2000]a)forming a reactant-prod...
Activation energy is the energy required to over come energy barrier of the reactants and make them reactive to start a chemical reaction. Enzymes lower the requirement of activation energy.
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Most Upvoted Answer
Enzymes enhance the rate of reaction by[2000]a)forming a reactant-prod...
Enzymes speed up reactions by lowering activation energy. The lower the activation energy of a rxn the faster will be the rate.
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Enzymes enhance the rate of reaction by[2000]a)forming a reactant-product complexb)changing the equilibrium point of the reactionc)combining with the product as soon as it is formedd)lowering the activation energy of the reactionCorrect answer is option 'D'. Can you explain this answer?
Question Description
Enzymes enhance the rate of reaction by[2000]a)forming a reactant-product complexb)changing the equilibrium point of the reactionc)combining with the product as soon as it is formedd)lowering the activation energy of the reactionCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Enzymes enhance the rate of reaction by[2000]a)forming a reactant-product complexb)changing the equilibrium point of the reactionc)combining with the product as soon as it is formedd)lowering the activation energy of the reactionCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Enzymes enhance the rate of reaction by[2000]a)forming a reactant-product complexb)changing the equilibrium point of the reactionc)combining with the product as soon as it is formedd)lowering the activation energy of the reactionCorrect answer is option 'D'. Can you explain this answer?.
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