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For a tachometer, if a(t) is the rotor displacement, e(t) is the output voltage and K is the tachometer constant, then the transfer function is given by:
  • a)
    Ks2
  • b)
    K/s
  • c)
    Ks
  • d)
    K
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
For a tachometer, if a(t) is the rotor displacement, e(t) is the outpu...
Explanation: e(t)=Kw
E(s)=Ksa(s)
E(s)/a(s)=Ks.
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Most Upvoted Answer
For a tachometer, if a(t) is the rotor displacement, e(t) is the outpu...
Explanation:

Transfer function is defined as the ratio of output to input in the Laplace domain. In the case of a tachometer, the input is the rotor displacement (a(t)) and the output is the output voltage (e(t)). The tachometer constant (K) is a parameter that relates the input and output.

The transfer function of a tachometer can be derived using the following steps:

1. Write the equation that relates the input and output:

e(t) = K * a(t)

2. Take the Laplace transform of both sides:

E(s) = K * A(s)

where E(s) and A(s) are the Laplace transforms of e(t) and a(t), respectively.

3. Divide both sides by A(s) to get the transfer function:

H(s) = E(s)/A(s) = K

Therefore, the transfer function is a constant value, which is equal to the tachometer constant (K).

Option C is the correct answer, which states that the transfer function is Ks/d. This is incorrect because the transfer function is a constant value (K) and does not have any s or d terms.
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For a tachometer, if a(t) is the rotor displacement, e(t) is the output voltage and K is the tachometer constant, then the transfer function is given by:a)Ks2b)K/sc)Ksd)KCorrect answer is option 'C'. Can you explain this answer?
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