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1cm3 of water at its boiling point absorbs 540 calories of heat to become steam with a volume of 1671 cm3. If the atmospheric pressure is 1.013 × 105 N/m2 and mechanical equivalent of heat = 4.19 J/calorie, the energy spent in this process in overcoming intermolecular forces is (in calories)
    Correct answer is '500'. Can you explain this answer?
    Verified Answer
    1cm3 of water at its boiling point absorbs 540 calories of heat to bec...
    Energy spent in overcoming intermolecular forces
    ΔU = ΔQ – ΔW
    = ΔQ – p(V2 – V1)

    = 500cal.
    The correct answer is: 500
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    Most Upvoted Answer
    1cm3 of water at its boiling point absorbs 540 calories of heat to bec...
    The given information allows us to calculate the heat of vaporization of water.

    First, we need to convert the volume of steam from cm³ to liters:
    1671 cm³ = 1671/1000 = 1.671 L

    Next, we can use the ideal gas law to calculate the number of moles of steam:
    PV = nRT
    n = PV/RT

    Here, P is the atmospheric pressure (1.013 atm), V is the volume of steam (1.671 L), R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

    Since the boiling point of water is 100°C or 373 K, we can substitute these values into the equation:
    n = (1.013 atm)(1.671 L) / (0.0821 L·atm/mol·K)(373 K)
    n ≈ 0.0697 mol

    Now, we can calculate the heat of vaporization using the formula:
    Heat of Vaporization = Heat Absorbed / Number of Moles

    Given that 1 cm³ of water absorbs 540 calories of heat, we can convert this to joules:
    1 calorie = 4.184 joules
    540 calories ≈ 540 * 4.184 joules ≈ 2258.16 joules

    Heat of Vaporization = 2258.16 joules / 0.0697 mol
    Heat of Vaporization ≈ 32,446.8 joules/mol

    Therefore, the heat of vaporization of water is approximately 32,446.8 joules/mol.
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    1cm3 of water at its boiling point absorbs 540 calories of heat to become steam with a volume of 1671 cm3. If the atmospheric pressure is 1.013 × 105 N/m2 and mechanical equivalent of heat = 4.19 J/calorie, the energy spent in this process in overcoming intermolecular forces is (in calories)Correct answer is '500'. Can you explain this answer?
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    1cm3 of water at its boiling point absorbs 540 calories of heat to become steam with a volume of 1671 cm3. If the atmospheric pressure is 1.013 × 105 N/m2 and mechanical equivalent of heat = 4.19 J/calorie, the energy spent in this process in overcoming intermolecular forces is (in calories)Correct answer is '500'. Can you explain this answer? for Physics 2024 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about 1cm3 of water at its boiling point absorbs 540 calories of heat to become steam with a volume of 1671 cm3. If the atmospheric pressure is 1.013 × 105 N/m2 and mechanical equivalent of heat = 4.19 J/calorie, the energy spent in this process in overcoming intermolecular forces is (in calories)Correct answer is '500'. Can you explain this answer? covers all topics & solutions for Physics 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 1cm3 of water at its boiling point absorbs 540 calories of heat to become steam with a volume of 1671 cm3. If the atmospheric pressure is 1.013 × 105 N/m2 and mechanical equivalent of heat = 4.19 J/calorie, the energy spent in this process in overcoming intermolecular forces is (in calories)Correct answer is '500'. Can you explain this answer?.
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