The price of a jewel varies as the square of its weight. Two jewels A ...
Suppose the weight of the jewel is W and its price is P then according to the question
P ∝ W2,
⇒ P = kW2 where K is the constant.
The ratio between the weights of A and B is 3 : 5. So let’s assume the weight of A is 3x and weight of B is 5x.
So, Price of A = k(3x)2 = 9kx2
And price of B = k(5x)2 = 25kx2
Now, weight of C = weight of A + weight of B = 3x + 5x = 8x
So, price of C = k(8x)2 = 64kx2
Combined price of A and B = 9kx2 + 25kx2 = 34kx2
So the required ratio = 64kx2 : 34kx2 = 32 : 17.
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The price of a jewel varies as the square of its weight. Two jewels A ...
Given:
- The price of a jewel varies as the square of its weight.
- The weights of jewels A and B are in the ratio of 3:5.
To find:
- The ratio of the price of jewel C to the combined price of jewels A and B.
Solution:
Let's assume the weight of jewel A as 3x (since the ratio of weights of A and B is 3:5) and the weight of jewel B as 5x.
Calculating the prices:
- The price of jewel A = (weight of A)^2 = (3x)^2 = 9x^2
- The price of jewel B = (weight of B)^2 = (5x)^2 = 25x^2
- The combined price of jewels A and B = 9x^2 + 25x^2 = 34x^2
Now, let's find the weight of jewel C.
- Jewel C is made by combining jewels A and B, so its weight is the sum of the weights of A and B.
- Weight of C = weight of A + weight of B = 3x + 5x = 8x
Now, let's calculate the price of jewel C using the given information that the price varies as the square of the weight.
- The price of jewel C = (weight of C)^2 = (8x)^2 = 64x^2
Calculating the ratio:
- The ratio of the price of C to the combined price of A and B = (price of C) / (combined price of A and B)
- Ratio = (64x^2) / (34x^2)
- Simplifying, Ratio = 64/34 = 32/17
Therefore, the ratio of the price of jewel C to the combined price of jewels A and B is 32:17, which is option B.