If LCM of two numbers is thrice the larger number and difference betwe...
Solution: Let the larger number be x and the smaller number be y.
It is given that LCM is thrice of the larger number,
Therefore, LCM = 3x ----(i)
It is also given that difference between the smaller number and the HCF is 14,
Therefore, y – HCF = 14
HCM = y – 14 ----(ii)
We know that product of two numbers = LCM × HCF
Therefore, x × y = 3x × (y – 14) (from (i) and (ii))
y = 3(y – 14)
y = 3y – 42
2y = 42
y = 21
Hence, the smaller number is 21.
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If LCM of two numbers is thrice the larger number and difference betwe...
Given Information:
- LCM of two numbers is thrice the larger number
- Difference between the smaller number and the HCF is 14
Solution:
Let's assume the two numbers are A and B, where A is the larger number and B is the smaller number.
Given:
- LCM(A,B) = 3A
- B - HCF(A,B) = 14
Expressing LCM in terms of HCF:
- LCM(A,B) = (A * B) / HCF(A,B)
Substitute the given values:
- 3A = (A * B) / HCF(A,B)
- 3A = AB / HCF(A,B)
Since A is the larger number, let's consider A = k * HCF(A,B) where k is a positive integer:
- 3(k * HCF(A,B)) = k * HCF(A,B) * B / HCF(A,B)
- 3k = B
Now, substitute B = 3k into the second equation:
- 3k - HCF(3k, k) = 14
- 3k - k = 14
- 2k = 14
- k = 7
Therefore, the smaller number B = 3k = 3 * 7 = 21.
So, the smaller number of the two numbers is 21, which corresponds to option 'C'.