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AB and CD are two parallel chords on the opposite sides of the centre of the circle. If AB = 18 cm, CD = 24 cm and the radius of the circle is 15 cm, the distance between the chords is
 
  • a)
    21 cm
  • b)
    24 cm
  • c)
    25 cm
  • d)
    27 cm
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
AB and CD are two parallel chords on the opposite sides of the centre ...
Perpendiculars drawn from the centre on the chord bisects them.
Given, AB and CD are two parallel chords on the opposite sides of the centre of the circle.
AB = 18 cm, CD = 24 cm and the radius of the circle is 15 cm
From the figure,
OM and OL are perpendiculars, OC and OA are radius
∴ CM = CD/2 = 12 cm and AL = AB/2 = 9 cm
By Pythagoras theorem:
OC2 = OM2 + MC2
⇒ OM2 = 152 – 122 = 81
⇒ OM = 9 cm
Similarly,
OA2 = OL2 + AL2
⇒ OL2 = 152 – 92 = 144
⇒ OL = 12 cm
Distance between the two chords = OL + OM
⇒ Distance between the two chord = 12 + 9 cm = 21 cm
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