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Pipe A and Pipe B can alone fill a tank in 20 hours and 30 hours, respectively and Pipe C alone can empty the tank in 15 hours. If pipe A opened alone for the first hour and Pipe B opened alone for the second hour and after the second hour all three pipes are opened, then the total time required to fill the tank is –
  • a)
    45 hours
  • b)
    57 hours
  • c)
    54 hours
  • d)
    49 hours
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Pipe A and Pipe B can alone fill a tank in 20 hours and 30 hours, resp...
Pipe A’s 1 hour’s work = 1/20
Pipe B’s 1 hour’s work = 1/30
Pipe C’s 1 hour’s work = 1/15
Pipe (A + B + C)’s 1 hour work
= 1/20 + 1/30 – 1/15
= 1/60
Tank filled in 1 hour = 1/20
Tank filled in the second hour = 1/30
Tank filled in the first two hours = 1/20 + 1/30 = 5/60 = 1/12
Tank remaining empty after two hours = 1 – 1/12 = 11/12
Time taken by three pipes = 11/12 × 60 = 55
∴ Total time required to fill the tank = 2 + 55 = 57 hours for given conditions.
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Most Upvoted Answer
Pipe A and Pipe B can alone fill a tank in 20 hours and 30 hours, resp...
First, let's find the rates at which each pipe can fill or empty the tank.

Pipe A fills the tank in 20 hours, so its filling rate is 1/20 tanks per hour.
Pipe B fills the tank in 30 hours, so its filling rate is 1/30 tanks per hour.
Pipe C empties the tank in 15 hours, so its emptying rate is 1/15 tanks per hour.

In the first hour, Pipe A fills 1/20 of the tank.
In the second hour, Pipe B fills 1/30 of the tank.

After the second hour, all three pipes are opened, so the total filling rate is the sum of the rates of Pipe A and Pipe B, minus the emptying rate of Pipe C:
1/20 + 1/30 - 1/15 = 3/60 + 2/60 - 4/60 = 1/60 tanks per hour.

To fill the entire tank, we need to fill 1 tank, and at a rate of 1/60 tanks per hour, it will take 60 hours.

Therefore, the total time required to fill the tank is 60 hours.
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Pipe A and Pipe B can alone fill a tank in 20 hours and 30 hours, respectively and Pipe C alone can empty the tank in 15 hours. If pipe A opened alone for the first hour and Pipe B opened alone for the second hour and after the second hour all three pipes are opened, then the total time required to fill the tank is –a)45 hoursb)57 hoursc)54 hoursd)49 hoursCorrect answer is option 'B'. Can you explain this answer?
Question Description
Pipe A and Pipe B can alone fill a tank in 20 hours and 30 hours, respectively and Pipe C alone can empty the tank in 15 hours. If pipe A opened alone for the first hour and Pipe B opened alone for the second hour and after the second hour all three pipes are opened, then the total time required to fill the tank is –a)45 hoursb)57 hoursc)54 hoursd)49 hoursCorrect answer is option 'B'. Can you explain this answer? for SSC JE 2024 is part of SSC JE preparation. The Question and answers have been prepared according to the SSC JE exam syllabus. Information about Pipe A and Pipe B can alone fill a tank in 20 hours and 30 hours, respectively and Pipe C alone can empty the tank in 15 hours. If pipe A opened alone for the first hour and Pipe B opened alone for the second hour and after the second hour all three pipes are opened, then the total time required to fill the tank is –a)45 hoursb)57 hoursc)54 hoursd)49 hoursCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for SSC JE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Pipe A and Pipe B can alone fill a tank in 20 hours and 30 hours, respectively and Pipe C alone can empty the tank in 15 hours. If pipe A opened alone for the first hour and Pipe B opened alone for the second hour and after the second hour all three pipes are opened, then the total time required to fill the tank is –a)45 hoursb)57 hoursc)54 hoursd)49 hoursCorrect answer is option 'B'. Can you explain this answer?.
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