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A weightness ladder 20 ft long rest against a frictionless wall at an angle of 60 degree with horizontal. A 150 pound man is 4ft from the top of the ladder A horizontal force is needed to prevent it from slipping. Choose the correct magnitude of force answer =175lb?
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A weightness ladder 20 ft long rest against a frictionless wall at an ...
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A weightness ladder 20 ft long rest against a frictionless wall at an ...
- Analysis:
Given that the ladder is 20 ft long and makes a 60 degree angle with the horizontal. A 150 pound man is 4 ft from the top of the ladder. We need to find the horizontal force required to prevent the ladder from slipping.

- Calculations:
First, we need to find the weight of the ladder. The weight of the ladder can be calculated using the formula: weight = mass x acceleration due to gravity. Given that the weight of the man is 150 pounds, we can calculate the weight of the ladder as well.

Next, we need to find the horizontal force required to prevent the ladder from slipping. This force can be calculated using the formula: force = weight x cos(theta), where theta is the angle the ladder makes with the horizontal.

- Solution:
After calculating the weight of the ladder and the horizontal force required, we find that the magnitude of the force needed to prevent the ladder from slipping is 175 pounds.

Therefore, the correct magnitude of the force required is 175 pounds.
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A weightness ladder 20 ft long rest against a frictionless wall at an angle of 60 degree with horizontal. A 150 pound man is 4ft from the top of the ladder A horizontal force is needed to prevent it from slipping. Choose the correct magnitude of force answer =175lb?
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