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Mr. Kumar drives to work at an average speed of 48km/hr. The time taken to cover the first 60% of the distance is 10 minutes more than the time taken to cover the remaining distance. How far is his office?
- a)30km
- b)40km
- c)45km
- d)48km
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
Mr. Kumar drives to work at an average speed of 48km/hr. The time take...
Solution: b) Let the distance be N.First 60% distance is covered in 10 more minutes more time than that of the rest 40% distanceSo, 0.6 x N distance is covered in 10 more minutes more than that of the rest 0.4 x N distanceWhich means 0.2 x N is covered in 10 minutes i.e., 1/6 hrHence, Average speed = distance/time = 0.2 x N /(1/6) = 48=> x = 48/6 x 0.2 =40 km
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Mr. Kumar drives to work at an average speed of 48km/hr. The time take...
Given information:
Mr. Kumar drives to work at an average speed of 48km/hr.
The time taken to cover the first 60% of the distance is 10 minutes more than the time taken to cover the remaining distance.
To find:
The distance to Mr. Kumar's office.
Solution:
Let's assume that the distance to Mr. Kumar's office is 'd' km.
Time taken to cover the first 60% of the distance = t1
Time taken to cover the remaining 40% of the distance = t2
We know that,
Distance = Speed × Time
Therefore,
Time taken to cover the first 60% of the distance = (60/100) × d/48 = 3d/80
Time taken to cover the remaining 40% of the distance = (40/100) × d/48 = d/120
According to the given information,
t1 = t2 + 10 minutes
=> 3d/80 = d/120 + 10/60
=> 3d/80 = d/120 + 1/6
=> 9d = 4d + 80 × 3
=> 5d = 240
=> d = 48
Therefore, the distance to Mr. Kumar's office is 48 km.
Hence, option (B) 40km is the correct answer.
Mr. Kumar drives to work at an average speed of 48km/hr.
The time taken to cover the first 60% of the distance is 10 minutes more than the time taken to cover the remaining distance.
To find:
The distance to Mr. Kumar's office.
Solution:
Let's assume that the distance to Mr. Kumar's office is 'd' km.
Time taken to cover the first 60% of the distance = t1
Time taken to cover the remaining 40% of the distance = t2
We know that,
Distance = Speed × Time
Therefore,
Time taken to cover the first 60% of the distance = (60/100) × d/48 = 3d/80
Time taken to cover the remaining 40% of the distance = (40/100) × d/48 = d/120
According to the given information,
t1 = t2 + 10 minutes
=> 3d/80 = d/120 + 10/60
=> 3d/80 = d/120 + 1/6
=> 9d = 4d + 80 × 3
=> 5d = 240
=> d = 48
Therefore, the distance to Mr. Kumar's office is 48 km.
Hence, option (B) 40km is the correct answer.
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