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25 litre of solution contains alcohol and water in the ratio 2:3. How much alcohol must be added to the solution to make a solution containing 60% of alcohol ?
- a)10.5 ltr
- b)11.5 ltr
- c)12.5 ltr
- d)13.5 ltr
Correct answer is option 'C'. Can you explain this answer?
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Verified Answer
25 litre of solution contains alcohol and water in the ratio 2:3. How ...
Answer – c) 12.5 ltr Solution: Initially alcohol 2/5 * 25 = 10 ltr and water is 15 ltr.
To make a solution of 60% alcohol (10+x)/25+x = 60/100. X = 12.5
To make a solution of 60% alcohol (10+x)/25+x = 60/100. X = 12.5
Most Upvoted Answer
25 litre of solution contains alcohol and water in the ratio 2:3. How ...
Given:
- A solution of 25 litres containing alcohol and water in the ratio 2:3
To find:
- How much alcohol must be added to the solution to make a solution containing 60% of alcohol
Solution:
1. Let's first find the amount of alcohol and water in the given solution:
- Let the amount of alcohol be 2x litres (since the ratio of alcohol to water is 2:3)
- Then, the amount of water must be 3x litres
- Total solution = 25 litres
- So, 2x + 3x = 25
- 5x = 25
- x = 5
- Therefore, the amount of alcohol in the given solution = 2x = 10 litres
- And, the amount of water in the given solution = 3x = 15 litres
2. Let's assume we need to add y litres of alcohol to the solution to make it contain 60% alcohol.
- After adding y litres of alcohol, the total amount of alcohol in the new solution = 10 + y litres
- Since we want the new solution to contain 60% alcohol, we can write:
(10 + y) / (25 + y) = 60/100
- Solving the above equation for y, we get:
y = 5
3. Therefore, we need to add 5 litres of alcohol to the given solution to make a solution containing 60% of alcohol.
Answer: Option (c) 12.5 litres
- A solution of 25 litres containing alcohol and water in the ratio 2:3
To find:
- How much alcohol must be added to the solution to make a solution containing 60% of alcohol
Solution:
1. Let's first find the amount of alcohol and water in the given solution:
- Let the amount of alcohol be 2x litres (since the ratio of alcohol to water is 2:3)
- Then, the amount of water must be 3x litres
- Total solution = 25 litres
- So, 2x + 3x = 25
- 5x = 25
- x = 5
- Therefore, the amount of alcohol in the given solution = 2x = 10 litres
- And, the amount of water in the given solution = 3x = 15 litres
2. Let's assume we need to add y litres of alcohol to the solution to make it contain 60% alcohol.
- After adding y litres of alcohol, the total amount of alcohol in the new solution = 10 + y litres
- Since we want the new solution to contain 60% alcohol, we can write:
(10 + y) / (25 + y) = 60/100
- Solving the above equation for y, we get:
y = 5
3. Therefore, we need to add 5 litres of alcohol to the given solution to make a solution containing 60% of alcohol.
Answer: Option (c) 12.5 litres
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25 litre of solution contains alcohol and water in the ratio 2:3. How ...
Answer – c) 12.5 ltr Solution: Initially alcohol 2/5 * 25 = 10 ltr and water is 15 ltr.
To make a solution of 60% alcohol (10+x)/25+x = 60/100. X = 12.5
To make a solution of 60% alcohol (10+x)/25+x = 60/100. X = 12.5
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25 litre of solution contains alcohol and water in the ratio 2:3. How much alcohol must be added to the solution to make a solution containing 60% of alcohol ?a)10.5 ltrb)11.5 ltrc)12.5 ltrd)13.5 ltrCorrect answer is option 'C'. Can you explain this answer?
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