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A bucket is filled with water such that the weight of bucket alone is 25% its weight when it is filled with water. Now some of the water is removed from the bucket and now the weight of bucket along with remaining water is 50% of the original total weight. What part of the water was removed from the bucket?
  • a)
    2/5
  • b)
    1/4
  • c)
    2/3
  • d)
    1/2
  • e)
    1/3
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A bucket is filled with water such that the weight of bucket alone is ...
C) 2/3
Explanation: Let original weight of bucket when it is filled with water = x Then weight of bucket = (25/100) * x = x/4 Original weight of water = x – (x/4) = 3x/4 Now when some water removed, new weight of bucket with remaining water = (50/100) * x = x/2 So new weight of water = new weight of bucket with remaining water – weight of bucket = [(x/2) – (x/4)] = x/4 So part of water removed = [(3x/4) – (x/4)]/(3x/4)
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Most Upvoted Answer
A bucket is filled with water such that the weight of bucket alone is ...
C) 2/3
Explanation: Let original weight of bucket when it is filled with water = x Then weight of bucket = (25/100) * x = x/4 Original weight of water = x – (x/4) = 3x/4 Now when some water removed, new weight of bucket with remaining water = (50/100) * x = x/2 So new weight of water = new weight of bucket with remaining water – weight of bucket = [(x/2) – (x/4)] = x/4 So part of water removed = [(3x/4) – (x/4)]/(3x/4)
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Community Answer
A bucket is filled with water such that the weight of bucket alone is ...
Given:
- Weight of bucket alone = 25% of weight of bucket when filled with water
- Weight of bucket + remaining water = 50% of original total weight

To find:
- Part of water removed from the bucket

Solution:
Let's assume the weight of the bucket when empty = x
Weight of bucket when filled with water = x + y (where y is the weight of water)
Given, weight of bucket alone = 25% of weight of bucket when filled with water
=> x = 0.25(x + y)
=> 0.75x = 0.25y
=> y = 3x

Now, weight of bucket + remaining water = 50% of original total weight
=> x + (3x - z) = 0.5(x + 3x)
=> x + 3x - z = 2x + 3x
=> z = 4x

Therefore, the weight of water removed from the bucket = 3x - z = 3x - 4x = -x
Since weight cannot be negative, it means that no water was removed from the bucket.

Hence, the correct answer is option (c) 2/3.
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