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In ∆ABC, AB = 12 cm, BC = 10 cm and AC = 6 cm. Find the approximate length of the median from vertex A.
  • a)
    8 cm
  • b)
    7 cm
  • c)
    10 cm
  • d)
    11 cm
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In ∆ABC, AB = 12 cm, BC = 10 cm and AC = 6 cm. Find the approxim...
As per the given data
Let AD be the length of the median subtending from vertex A and to the side BC
⇒ BD = DC = BC/2 = 10/2 = 5 cm
By Apollonius theorem, we get
⇒ AB2 + AC2 = 2 (AD2 + BD2)
⇒ 122 + 6= 2 (AD2 + 52)
⇒ 90 = AD2 + 25
⇒ 65 = AD2
⇒ AD = 8.06 cm
∴ length of the medium = AD = 8.06 ≈ 8 cm
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Most Upvoted Answer
In ∆ABC, AB = 12 cm, BC = 10 cm and AC = 6 cm. Find the approxim...
Given: AB = 12 cm, BC = 10 cm and AC = 6 cm
To find: Approximate length of median from vertex A

Median of a triangle is a line segment joining a vertex to the midpoint of the opposite side. Let's assume D as the midpoint of BC.

Steps:
1. Find the value of BD and DC using the formula of midpoint. BD = DC = BC/2 = 10/2 = 5 cm
2. Using the Pythagorean theorem, find the value of AD.
AD^2 = AB^2 - BD^2
= 12^2 - 5^2
= 119
AD = √119 ≈ 10.9 cm
3. The median from vertex A divides the side BC into two equal parts.
Therefore, the length of BM = MC = BC/2 = 5 cm
4. Using the Pythagorean theorem, find the value of AM.
AM^2 = AD^2 - DM^2
= 119 - 5^2
= 94
AM = √94 ≈ 9.7 cm
5. The approximate length of the median from vertex A is the average of BM and AM.
Median from vertex A ≈ (BM + AM)/2
= (5 + 9.7)/2
= 7.35 ≈ 8 cm

Therefore, the approximate length of the median from vertex A is 8 cm, which is option (a)
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In ∆ABC, AB = 12 cm, BC = 10 cm and AC = 6 cm. Find the approximate length of the median from vertex A.a)8 cmb)7 cmc)10 cmd)11 cmCorrect answer is option 'A'. Can you explain this answer?
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