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 A vendor sells 50 percent of apples he had and throws away 20 percent of the remainder. Next day he sells 60 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?

  • a)
    20%

  • b)
    22%

  • c)
    24%

  • d)
    26%

  • e)
    None of these

Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A vendor sells 50 percent of apples he had and throws away 20 percent ...
Let the total number of apples the vendor initially had be 100 (for simplicity).
On the first day:
The vendor sells 50% of the apples:
Apples sold on day 1 = 50% of 100 = 50
The remaining apples after selling 50% are:
Remaining apples = 100 − 50 = 50
He then throws away 20% of the remaining apples:
Apples thrown away on day 1 = 20% of 50 = 10
The remaining apples after throwing away 20% are:
Remaining apples after day 1 = 50 − 10 = 40
On the second day:
The vendor sells 60% of the remaining apples:
Apples sold on day 2 = 60% of 40 = 24
The remaining apples after selling 60% are:
Remaining apples after selling on day 2 = 40 − 24 = 16
He throws away the rest, which is 16 apples.
Total apples thrown away:
Apples thrown away on day 1 = 10
Apples thrown away on day 2 = 16
Total apples thrown away = 10 + 16 = 26
Percentage of apples thrown away:

Thus, the vendor throws away 26% of his apples.
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Most Upvoted Answer
A vendor sells 50 percent of apples he had and throws away 20 percent ...
Answer – d) 26% Explanation : Let total apples be 100 first day he throws = 50*20/100 = 10 apples next day he throws = 40*40/100 = 16 (if he sells 60% then he must throw 40% according to question)apples so total = 26
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Community Answer
A vendor sells 50 percent of apples he had and throws away 20 percent ...
Here's the explanation to your question:

Let total apples be 100 first day he throws = 50*20/100 = 10 apples next day he throws = 40*40/100 = 16 apples so total = 26

Hence option (D) is correct

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