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In an election 10% of the voters on the voters’ list did not cast votes and 60 voters cast their ballot papers blank. There were only two candidates. The winner was supported by 47% of all voters in the list and he got 308 votes more than his rival. The number of voters on the list was:
  • a)
    3600
  • b)
    6200
  • c)
    4575
  • d)
    6028
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
In an election 10% of the voters on the voters’ list did not cas...
B. 6200
Explanation: Let total number of voters= x People who voted for the winner are = 0.47x People who voted for the loser are = 0.47x-308 People who cast blanks are = 60 and people who did not vote are = 0.1x solve the following equation 0.47x+0.47x-308+60+0.1x=x => x=6200
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Most Upvoted Answer
In an election 10% of the voters on the voters’ list did not cas...
List did not vote. If there are 1,000 voters on the list, then 10% of them did not vote, which is:

10% of 1,000 = (10/100) x 1,000 = 100

So, 100 voters did not vote.

If the remaining 90% of voters did vote, then the number of voters who did vote is:

90% of 1,000 = (90/100) x 1,000 = 900

Therefore, the number of voters who did vote is 900.
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In an election 10% of the voters on the voters’ list did not cast votes and 60 voters cast their ballot papers blank. There were only two candidates. The winner was supported by 47% of all voters in the list and he got 308 votes more than his rival. The number of voters on the list was:a)3600b)6200c)4575d)6028Correct answer is option 'B'. Can you explain this answer?
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