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A plant with genotype ab/ab is crossed with Ab/ab Plant. in this cross 1800 out of 3000 individual are parental type . then the distance between a and b gene is ? 1) 40 map unit 2) 60 map unit 3)20 map unit 4)18 map unit?
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A plant with genotype ab/ab is crossed with Ab/ab Plant. in this cross...
Solution:

Given,
One parent plant has genotype ab/ab and the other parent plant has genotype Ab/ab.
Out of 3000 individuals, 1800 individuals are parental types.

Step 1: Determine the genotypes of the parent plants.
When the two parent plants with genotypes ab/ab and Ab/ab are crossed, the possible gametes they can produce are:
ab and Ab from the first parent
a and b from the second parent

So, the possible offspring genotypes are:
ab/aAb, ab/ab, Ab/aAb, Ab/ab

Step 2: Determine the parental type and recombinant type offspring.
Out of the 3000 offspring, 1800 are parental types. These are the offspring that have the same genotype as one of the parent plants (ab/ab or Ab/ab). The remaining 1200 offspring are recombinant types.

Step 3: Calculate the recombination frequency.
Recombination frequency = (number of recombinant offspring / total number of offspring) x 100%
Recombination frequency = (1200 / 3000) x 100%
Recombination frequency = 40%

Step 4: Calculate the distance between the two genes.
Since the recombination frequency is 40%, the distance between the two genes (a and b) is 40 map units.

Answer:
The distance between the a and b gene is 40 map unit.

Note:
The higher the recombination frequency, the farther apart the two genes are on the chromosome. A recombination frequency of 50% indicates that the two genes are located on different chromosomes.
Community Answer
A plant with genotype ab/ab is crossed with Ab/ab Plant. in this cross...
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A plant with genotype ab/ab is crossed with Ab/ab Plant. in this cross 1800 out of 3000 individual are parental type . then the distance between a and b gene is ? 1) 40 map unit 2) 60 map unit 3)20 map unit 4)18 map unit?
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