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A tank is filled in 10 hours by three pipes A, B and C. Pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?
  • a)
    70 hours
  • b)
    30 hours
  • c)
    35 hours
  • d)
    50 hours
Correct answer is option 'A'. Can you explain this answer?
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A tank is filled in 10 hours by three pipes A, B and C. Pipe C is twic...
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A tank is filled in 10 hours by three pipes A, B and C. Pipe C is twic...
Given information:
- Pipe C is twice as fast as B.
- Pipe B is twice as fast as A.

Let's assume that pipe A takes x hours to fill the tank alone.

Pipe B is twice as fast as A, so it will take x/2 hours to fill the tank alone.

Similarly, pipe C is twice as fast as B, so it will take (x/2)/2 = x/4 hours to fill the tank alone.

Now, let's calculate the rates of each pipe:
- Pipe A fills 1/x of the tank in one hour.
- Pipe B fills 1/(x/2) = 2/x of the tank in one hour.
- Pipe C fills 1/(x/4) = 4/x of the tank in one hour.

The combined rate of all three pipes is equal to the rate at which the tank is filled in 10 hours.
So, the combined rate is 1/10 of the tank per hour.

Now, let's set up the equation:
1/x + 2/x + 4/x = 1/10

Combining the fractions, we get:
7/x = 1/10

Cross-multiplying, we get:
7 * 10 = x
70 = x

Therefore, pipe A alone will take 70 hours to fill the tank.

Hence, the correct answer is option A) 70 hours.
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A tank is filled in 10 hours by three pipes A, B and C. Pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?a)70 hoursb)30 hoursc)35 hoursd)50 hoursCorrect answer is option 'A'. Can you explain this answer?
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